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The area of the right triangle below is 2√3. What is the length of the
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16 Feb 2022, 06:00
16 Feb 2022, 06:00
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The area of the right triangle below is 2√3. What is the length of the altitude h?
GRE The area of the right triangle below.jpg [ 12.28 KiB | Viewed 1462 times ]
(A) √2
(B) √3
(C) 2
(D) 2√2
(E) 3
Attachment:
GRE The area of the right triangle below.jpg [ 12.28 KiB | Viewed 1462 times ]
(A) √2
(B) √3
(C) 2
(D) 2√2
(E) 3
The area of the right triangle below is 2√3. What is the length of the
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16 Feb 2022, 11:03
16 Feb 2022, 11:03
1
Lets find length of other side --> 1/2 * other side * 2 = 2\(\sqrt{3} ==> 2\sqrt{3}\)
Apply Pythagoras to bigger triangle \(2^2 + (2\sqrt{3})^2 = 4 +12 = \sqrt{16} ==> 4\)
So we can calculate the area of triangle again using the altitude ==> \(\frac{1}{2} * 4 * h = 2\sqrt{3} ==>> h =\sqrt{3}\)
Apply Pythagoras to bigger triangle \(2^2 + (2\sqrt{3})^2 = 4 +12 = \sqrt{16} ==> 4\)
So we can calculate the area of triangle again using the altitude ==> \(\frac{1}{2} * 4 * h = 2\sqrt{3} ==>> h =\sqrt{3}\)
Re: The area of the right triangle below is 23. What is the length of the
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04 Jun 2024, 19:24
04 Jun 2024, 19:24
AkkuJi wrote:
Lets find length of other side --> 1/2 * other side * 2 = 2\(\sqrt{3} ==> 2\sqrt{3}\)
Apply Pythagoras to bigger triangle \(2^2 + (2\sqrt{3})^2 = 4 +12 = \sqrt{16} ==> 4\)
So we can calculate the area of triangle again using the altitude ==> \(\frac{1}{2} * 4 * h = 2\sqrt{3} ==>> h =\sqrt{3}\)
Apply Pythagoras to bigger triangle \(2^2 + (2\sqrt{3})^2 = 4 +12 = \sqrt{16} ==> 4\)
So we can calculate the area of triangle again using the altitude ==> \(\frac{1}{2} * 4 * h = 2\sqrt{3} ==>> h =\sqrt{3}\)
Can you please explain it how base is taken as 4??
So we can calculate the area of triangle again using the altitude ==> \(\frac{1}{2} * 4 * h = 2\sqrt{3} ==>> h =\sqrt{3}\)[/quote]
