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The average (arithmetic mean) of m and n is 1 more than k
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06 Nov 2019, 09:27
06 Nov 2019, 09:27
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The average (arithmetic mean) of m and n is 1 more than k
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(m+n\) |
\(2k+1\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: The average (arithmetic mean) of m and n is 1 more than k
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07 Nov 2019, 08:56
07 Nov 2019, 08:56
1
Carcass wrote:
The average (arithmetic mean) of m and n is 1 more than k
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(m+n\) |
\(2k+1\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
We can write: (average of m and n) \(= k + 1\)
This means: \(\frac{m+n}{2} = k + 1\)
Multiply both sides by 2 to get: \(m+n = 2k + 2\)
GIVEN:
QUANTITY A: \(m+n\)
QUANTITY B: \(2k+1\)
Replace \(m+n\) with \(2k + 2\) to get:
QUANTITY A: \(2k+2\)
QUANTITY B: \(2k+1\)
Subtract \(2k\) from both quantities to get:
QUANTITY A: \(2\)
QUANTITY B: \(1\)
Answer: A
Cheers,
Brent
Re: The average (arithmetic mean) of m and n is 1 more than k
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17 May 2025, 14:44
17 May 2025, 14:44
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