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The circle shown has center T. The measure of angle TVU is 6
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15 Oct 2018, 09:44
15 Oct 2018, 09:44
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The circle shown has center T. The measure of angle TVU is 60 °. If the circle has a radius of 3, what is the length of segment RS?
A. 2
B. \(2 \sqrt{2}\)
C. 3
D. \(3 \sqrt{3}\)
E. \(6 \sqrt{2}\)
Re: The circle shown has center T. The measure of angle TVU is 6
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18 Oct 2018, 07:22
18 Oct 2018, 07:22
Carcass wrote:
Attachment:
circle.jpg
The circle shown has center T. The measure of angle TVU is 60 °. If the circle has a radius of 3, what is the length of segment RS?
A. 2
B. \(2 \sqrt{2}\)
C. 3
D. \(3 \sqrt{3}\)
E. \(6 \sqrt{2}\)
We are told that T is the center then TU and TV are the radius of the circle and the value is 3, since both sides are same the angles TVU and TUV are 60, then obviously the other angle will be 60 degrees, it is an equilateral triangle.
We know that for an equilateral triangle all sides are equal , VU is 3. The other triangle has in sync with the TUV triangle, RS is 3.
C.
Re: The circle shown has center T. The measure of angle TVU is 6
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14 May 2025, 12:36
14 May 2025, 12:36
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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