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Re: The perimeter of ∆ABC [#permalink]
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sum of arcs > sum of chords

Hence B
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The perimeter of ABC [#permalink]
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Let's consider a circle with a circumference of 4π, thus diameter = 4.

If it was possible to build an equilateral triangle with 3 diameters in length (each side) within the circle (biggest possible chord), then its perimeter would be 3x2 = 6.
But the circumference is 4π > 12. So it must be the case that B > A.
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The perimeter of ABC [#permalink]
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