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The probability is 1/2 that a certain coin will turn up head
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03 Sep 2020, 10:27
03 Sep 2020, 10:27
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The probability is 1/2 that a certain coin will turn up heads on any given toss. If the coin is to be tossed three times, what is the probability that on at least one of the tosses the coin will turn up tails?
(A) 1/8
(B) 1/2
(C) 3/4
(D) 7/8
(E) 15/16
(A) 1/8
(B) 1/2
(C) 3/4
(D) 7/8
(E) 15/16
Re: The probability is 1/2 that a certain coin will turn up head
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03 Sep 2020, 10:28
03 Sep 2020, 10:28
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
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Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
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Re: The probability is 1/2 that a certain coin will turn up head
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03 Sep 2020, 11:28
03 Sep 2020, 11:28
Carcass wrote:
The probability is 1/2 that a certain coin will turn up heads on any given toss. If the coin is to be tossed three times, what is the probability that on at least one of the tosses the coin will turn up tails?
(A) 1/8
(B) 1/2
(C) 3/4
(D) 7/8
(E) 15/16
(A) 1/8
(B) 1/2
(C) 3/4
(D) 7/8
(E) 15/16
When it comes to probability questions involving "at least," it's best to try using the complement.
That is, P(Event A happening) = 1 - P(Event A not happening)
So, here we get: P(getting at least 1 tails) = 1 - P(not getting at least 1 tails)
What does it mean to not get at least 1 tails? It means getting zero tails.
So, we can write: P(getting at least 1 tails) = 1 - P(getting zero tails)
Now let's calculate P(getting zero tails)
What needs to happen in order to get zero tails?
Well, we need heads on the first toss and heads on the second toss and heads on the third toss.
We can write P(getting zero tails) = P(heads on 1st AND heads on 2nd AND heads on 3rd)
This means that P(getting zero tails) = P(heads on 1st) x P(heads on 2nd) x P(heads on 3rd)
Which means P(getting zero tails) = (1/2)x(1/2)x(1/2)= 1/8
We're now ready to answer the question.
P(getting at least 1 tails) = 1 - P(not getting at least 1 tails)
= 1 - 1/8
= 7/8
Answer: D
Cheers,
Brent
