GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The sides of a triangle are $x, y$ and $z$. If $z=\frac{1}{4}$ (perime
[#permalink]
17 Feb 2025, 00:57
17 Feb 2025, 00:57
Expert Reply
00:00
Question Stats:
100% (00:54) correct
0% (00:00) wrong based on 4 sessions
Hide Show timer Statistics
The sides of a triangle are $\(x, y\)$ and $\(z\)$. If $\(z=\frac{1}{4}\)$ (perimeter of the triangle) and $\(x+y=12\)$, what is the perimeter of the triangle?
(A) 12
(B) 14
(C) 16
(D) 18
(E) 20
(A) 12
(B) 14
(C) 16
(D) 18
(E) 20
- Part of the project: GRE Quant & Verbal ADVANCED Daily Challenge 2025 NEW Edition - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
- Also replying to the unanswered questions
Re: The sides of a triangle are $x, y$ and $z$. If $z=\frac{1}{4}$ (perime
[#permalink]
11 Mar 2025, 11:17
11 Mar 2025, 11:17
Expert Reply
The sides of the triangle are $\(\mathrm{x}, \mathrm{y}\)$ and z .
Using $\(x+y=12\)$, we get $\(z=\frac{1}{4}(\)$ Perimeter of the triangle $\()=\frac{1}{4}(x+y+z)=\frac{1}{4}(12+z)\)$ which when simplified gives $\(z=4\)$
So, the perimeter of the triangle is sum of sides $\(=x+y+z=12+4=16\)$
Hence the answer is (C).
Using $\(x+y=12\)$, we get $\(z=\frac{1}{4}(\)$ Perimeter of the triangle $\()=\frac{1}{4}(x+y+z)=\frac{1}{4}(12+z)\)$ which when simplified gives $\(z=4\)$
So, the perimeter of the triangle is sum of sides $\(=x+y+z=12+4=16\)$
Hence the answer is (C).
gmatclubot
Re: The sides of a triangle are $x, y$ and $z$. If $z=\frac{1}{4}$ (perime [#permalink]
11 Mar 2025, 11:17
Moderators:
