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the standard deviation of set F
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26 Aug 2022, 04:53
26 Aug 2022, 04:53
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Question Stats:
87% (00:17) correct
12% (00:26) wrong based on 8 sessions
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F = {28, 29, 30, 31, 32}
G = {10, 20, 30, 40, 50}
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
G = {10, 20, 30, 40, 50}
Quantity A |
Quantity B |
the standard deviation of set F |
the standard deviation of set G |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Re: the standard deviation of set F
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26 Aug 2022, 07:09
26 Aug 2022, 07:09
2
F = {28, 29, 30, 31, 32}
G = {10, 20, 30, 40, 50}
Since sets have a uniform gap in between elements; Mean = Median
Mean of F = 30
Mean of G = 30
SD is square root of variance. Variance is a measure of sparseness of teh set (Distance of elements from their mean)
By mere looking, we can see that Set F is more clustered (less distance between mean and other values. Set G is more sparse (A gap of atleast 10 between mean and other values)
Since, Variance in Set G > Variance in Set F
S.D in Set G > S.D in Set F
Answer is B
G = {10, 20, 30, 40, 50}
Since sets have a uniform gap in between elements; Mean = Median
Mean of F = 30
Mean of G = 30
SD is square root of variance. Variance is a measure of sparseness of teh set (Distance of elements from their mean)
By mere looking, we can see that Set F is more clustered (less distance between mean and other values. Set G is more sparse (A gap of atleast 10 between mean and other values)
Since, Variance in Set G > Variance in Set F
S.D in Set G > S.D in Set F
Answer is B
gmatclubot
Re: the standard deviation of set F [#permalink]
26 Aug 2022, 07:09
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