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A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
Re: List A and List B
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20 Nov 2017, 18:48
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Technically, the GRE requires you to know standard deviation. In reality, however, you really only need to understand the basic concepts behind standard deviation, because the equation for standard deviation is a big mess.
What is standard deviation, in words? In any list of numbers, standard deviation is the square root of the variance (the variance is the average of the squared distances from the mean). Yes, I know that's confusing.
Standard deviation is basically a measure of spacing, and is related (although not solely determined) by the range of the numbers in the list. If the range (high term - low term) is the same, then the standard deviation is also the same, so long as the numbers are spread out equally in both lists.
One compromise between range and actual standard deviation is what's called average standard deviation (ASV). To date, no one has ever seen an official GRE question that requires you to do more than calculate ASV.
To calculate ASV:
1) find the mean.
2) add up all the distances from the mean, then divide by the number of terms.
That's it. Yes, ASV is not the same thing as standard deviation, but on the GRE you don't need to know the exact equation for standard deviation, at least not yet, so this shortcut should be sufficient.
Let’s try the ASV method for Quantity A and Quantity B. The average of list A is 10, and the average of list B is 15, because the average of a list of consecutive, evenly spaced numbers is equal to the median of those numbers.
Now, let’s add up the distances from the mean and divide by 5. Quantity A: (10+5+0+5+10) / 5 = 30/5 = 6. Quantity B: (10+5+0+5+10) = 30/5 = 6. Thus, the ASV of both lists are equal, so it is highly likely that their Standard Deviations are also equal.
If you are perhaps paranoid that you will be the one unfortunate GRE test-taker in history who will be asked to calculate standard deviation exactly, then here is how to do so:
-Determine the Mean. (Mean = Average = Total / # of things) -For each number, subtract the mean and square the result. -Determine the mean of all the squared differences. -Take the root of your answer. That is the standard deviation.
If you really, really, want to geek out on this, then you can read about the differences between the “n version” (less common) and “n-1” (default) version here: N vs N-1 when calculating Standard Deviation
There are 3 rather easy standard deviation questions included in the Official Guide to the GRE, 2nd Edition, including one (#9 page 401) that requires memorization of the 34, 14, 2 Rule (check out pages 107, 138-141, 149, 174, 273-275, 285-291, 296-300, 331, 401, 460 and 535 for mentions of standard deviation). However, I’ve yet to see a question on the actual GRE where using the formula for Standard Deviation was necessary--in fact, the formula itself nowhere to be found anywhere in the book. So I wouldn’t worry much about having to memorize it exactly unless you’re going for a perfect 170 on math and don’t want to take any chances. In which case, you probably already know the formula.
Anyway, here’s the easy solution:
Range of list A (high - low) = 20 - 0 = 20
Range of list B (high- low) = 25 - 5 = 20
The two lists have the same ranges, and the numbers in each list are spread out exactly the same: consecutive multiples of 5. Thus we can conclude that their standard deviations are the same.
Think of it another way. Standard deviation is a measure of the spacing (from the average term) of numbers in a list, regardless of the value of the average. Well, if all the numbers in List A stood up at the same time and took five steps to the right on the number line, then they would create List B. Yes, the numbers in List B are greater, which might tempt some to choose Choice B, but the spacing of List B is exactly the same as that of List A.
The answer is Choice C--the standard deviations of both lists are equal.
Harvard grad and verified 99% GRE scorer, offering high-quality private GRE tutoring and coaching, both in-person (San Diego, CA, USA) and online worldwide, since 2002.
Re: List A and List B
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04 Feb 2017, 19:43
3
Expert Reply
Explanation
We do not need to solve the standard deviation of two list to get the answer to this one. Standard deviation is measure of extreme point from the central points, the minimum and maximum from the mean. It is independent of the number itself.
We can clearly see that all elements of List B is elements of List A +5.
Hence intuitively we can answer that Quantity A = Quantity B.
Hence option C is correct. _________________
Sandy If you found this post useful, please let me know by pressing the Kudos Button
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
The standard deviation measures the dispersion of a set of numbers. In this case, each set is equally dispersed. Each set has 5 numbers, and each number is 5 greater than the number before it.
As such, we can conclude that the standard deviation of the numbers in List A = the standard deviation of the numbers in List B
-----ASIDE---------------------------- For the purposes of the GRE, it's sufficient to think of Standard Deviation as the Average Distance from the Mean. Here's what I mean:
Consider these two sets: Set A {7,9,10,14} and set B {1,8,13,18} The mean of set A = 10 and the mean of set B = 10 How do the Standard Deviations compare? Well, since the numbers in set B deviate the more from the mean than do the numbers in set A, we can see that the standard deviation of set B must be greater than the standard deviation of set A.
Alternatively, let's examine the Average Distance from the Mean for each set.
Set A {7,9,10,14} Mean = 10 7 is a distance of 3 from the mean of 10 9 is a distance of 1 from the mean of 10 10 is a distance of 0 from the mean of 10 14 is a distance of 4 from the mean of 10 So, the average distance from the mean = (3+1+0+4)/4 = 2
B {1,8,13,18} Mean = 10 1 is a distance of 9 from the mean of 10 8 is a distance of 2 from the mean of 10 13 is a distance of 3 from the mean of 10 18 is a distance of 8 from the mean of 10 So, the average distance from the mean = (9+2+3+8)/4 = 5.5
IMPORTANT: I'm not saying that the Standard Deviation of set A equals 2, and I'm not saying that the Standard Deviation of set B equals 5.5 (They are reasonably close however).
What I am saying is that the average distance from the mean can help us see that the standard deviation of set B must be greater than the standard deviation of set A. More importantly, the average distance from the mean is a useful way to think of standard deviation. This model is a convenient way to handle most standard deviation questions on the GRE.
------NOW ONTO THE QUESTION-----
List A: 0, 5, 10, 15, 20 The mean = 10 0 is a distance of 10 from the mean of 10 5 is a distance of 5 from the mean of 10 10 is a distance of 0 from the mean of 10 15 is a distance of 5 from the mean of 10 20 is a distance of 10 from the mean of 10
List B: 5, 10, 15, 20, 25 The mean = 15 5 is a distance of 10 from the mean of 15 10 is a distance of 5 from the mean of 15 15 is a distance of 0 from the mean of 15 20 is a distance of 5 from the mean of 15 25 is a distance of 10 from the mean of 15
For each value in BOTH lists, the distances to the means are EQUAL
So, the two sets must have EQUAL Standard Deviations
Re: The standard deviation of the numbers in List A
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31 Aug 2022, 10:47
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