We are told that the median is 45
In other words, when all of the consecutive numbers are arranged in ascending order, 45 is the middlemost number.
Now let's add a number on either side of 45 to get: 44, 45, 46
This is the same as writing: (45-1), 45, (45+1), and if we add these three values, the -1 and +1 cancel out to get: 45 + 45 + 45


The same applies to when we add TWO numbers on either side of 45
We get: (45-2), (45-1), 45, (45+1), (45+2)
If we add these five values, the -1 and +1 cancel out, and the -2 and +2 cancel out to get : 45 + 45 + 45 + 45 + 45

1,125/45 = 25
So our sequence must consist of 25 values.
12 values must be greater than 45
12 values must be less than 45
And 1 value is equal to 45

So our sequence looks like this: (45-12), (45-11), (45-10), ..... (45-2), (45-1), 45, (45+1), (45+2)...., (45+10), (45+11), (45+12)

What is the value of the greatest integer in the sequence?
The greatest possible value = (45+12), which equals 57

Answer: D

Cheers,
Brent