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The sum of k consecutive integers is 41. If the least intege
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14 Mar 2019, 10:47
14 Mar 2019, 10:47
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47% (01:06) correct
52% (01:10) wrong based on 78 sessions
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The sum of k consecutive integers is 41. If the least integer is –40, then k =
A. 40
B. 41
C. 80
D. 81
E. 82
A. 40
B. 41
C. 80
D. 81
E. 82
Re: The sum of k consecutive integers is 41. If the least intege
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20 Mar 2019, 15:13
20 Mar 2019, 15:13
4
Expert Reply
The least integer is -40, then -39, and so on, until we get to 0. Then we have positive integers, 1, 2...39, 40. Each of the 40 negative integers will be canceled out by 40 positive integers, so that the sum up to 40 is 0.
The next integer is 41, making the sum of the whole list 41.
So we have 40 negative integers, canceled out by 40 positive integers. That's 80 integers in all.
Then, 41 is our 81st integers, and we can't forget 0 as our 82nd. So there are 82 integers on this list, and k = 82.
The next integer is 41, making the sum of the whole list 41.
So we have 40 negative integers, canceled out by 40 positive integers. That's 80 integers in all.
Then, 41 is our 81st integers, and we can't forget 0 as our 82nd. So there are 82 integers on this list, and k = 82.
The sum of k consecutive integers is 41. If the least intege
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15 Aug 2022, 19:09
15 Aug 2022, 19:09
1
Small scale experiment.
Let's rephrase the prompt.
The sum of k consecutive integers is 3. If the least integer is –2, then k =
-2 -1 0 1 2 3
It is clear that the two negatives are canceled by the two positives. We then need to add two numbers: 0 and 3 to get our final sum. In our small sample, K = 8.
Scaling up: -40 ---- 0 ---- +40 ---- 41
K = 82
Let's rephrase the prompt.
The sum of k consecutive integers is 3. If the least integer is –2, then k =
-2 -1 0 1 2 3
It is clear that the two negatives are canceled by the two positives. We then need to add two numbers: 0 and 3 to get our final sum. In our small sample, K = 8.
Scaling up: -40 ---- 0 ---- +40 ---- 41
K = 82
