If m and n are the roots of the equation
[#permalink]
Updated on: 18 Aug 2018, 02:03
HI guys!
Question:
If m and n are the roots of the equation \(a^2 - 6a + 8 = 0\), then find the value of \((m+n)(m-n)\)
A. 12
B. 8
C. 16
D. 4
E.18
Now, the answer should be 12, because the fractioning of the equation gets me (a-4) (a-2). However, what if I switched places here and put (a-2) (a-4). Then, m = 2 and n=4, thus (2+4) (2-4) = -12. Where am I going wrong? Sorry for this stupid question. And btw, roots of the equation are always positive then, right?
Appreciate any help.
Originally posted by
sdw on 18 Aug 2018, 00:39.
Last edited by
Carcass on 18 Aug 2018, 02:03, edited 1 time in total.
Edited by Carcass