GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Exponents question
[#permalink]
23 Nov 2015, 16:08
23 Nov 2015, 16:08
2
00:00
Question Stats:
81% (00:41) correct
18% (01:45) wrong based on 11 sessions
Hide Show timer Statistics
Hi all, so I have a question on this exponents question.
Quant A: (5^x)/(5^(x-1))
Quant B: (5^(x-1))/(5^(x-2))
x>0
The answer is that two quantities are equal.
I understand that A: 5^(x-x+1)=5 and B: 5^(x-1-x+2)=5, thus A and B are equal, but what about the case where x=1?
Then A would be 5 over zero, and B would be zero over 1/5. In this case, A and B are not equal. So should the relationship be indeterminable?
Quant A: (5^x)/(5^(x-1))
Quant B: (5^(x-1))/(5^(x-2))
x>0
The answer is that two quantities are equal.
I understand that A: 5^(x-x+1)=5 and B: 5^(x-1-x+2)=5, thus A and B are equal, but what about the case where x=1?
Then A would be 5 over zero, and B would be zero over 1/5. In this case, A and B are not equal. So should the relationship be indeterminable?
Attachments
Capture.PNG [ 3.2 KiB | Viewed 3619 times ]
Re: Exponents question
[#permalink]
23 Nov 2015, 16:52
23 Nov 2015, 16:52
Expert Reply
Estrella wrote:
Hi all, so I have a question on this exponents question.
Quant A: (5^x)/(5^(x-1))
Quant B: (5^(x-1))/(5^(x-2))
x>0
The answer is that two quantities are equal.
I understand that A: 5^(x-x+1)=5 and B: 5^(x-1-x+2)=5, thus A and B are equal, but what about the case where x=1?
Then A would be 5 over zero, and B would be zero over 1/5. In this case, A and B are not equal. So should the relationship be indeterminable?
Quant A: (5^x)/(5^(x-1))
Quant B: (5^(x-1))/(5^(x-2))
x>0
The answer is that two quantities are equal.
I understand that A: 5^(x-x+1)=5 and B: 5^(x-1-x+2)=5, thus A and B are equal, but what about the case where x=1?
Then A would be 5 over zero, and B would be zero over 1/5. In this case, A and B are not equal. So should the relationship be indeterminable?
Hey Estrella,
\(5^0=1\) not 0 so even if x=1 the equality holds.
Regards,
