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If (x + 1)^2 – 2x > 2(x + 1) + 2, then x cannot equal
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28 Mar 2019, 13:10
28 Mar 2019, 13:10
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Question Stats:
86% (01:15) correct
13% (01:38) wrong based on 30 sessions
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If \((x + 1)^2 – 2x > 2(x + 1) + 2\), then x cannot equal which one of the following?
(A) –5
(B) –3
(C) 0
(D) 3
(E) 5
(A) –5
(B) –3
(C) 0
(D) 3
(E) 5
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Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If (x + 1)^2 – 2x > 2(x + 1) + 2, then x cannot equal
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28 Mar 2019, 13:25
28 Mar 2019, 13:25
1
Carcass wrote:
If \((x + 1)^2 – 2x > 2(x + 1) + 2\), then x cannot equal which one of the following?
(A) –5
(B) –3
(C) 0
(D) 3
(E) 5
(A) –5
(B) –3
(C) 0
(D) 3
(E) 5
Given: (x + 1)² – 2x > 2(x + 1) + 2
Expand both sides to get: x² + 2x + 1 – 2x > 2x + 2 + 2
Simplify both sides to get: x² + 1 > 2x + 4
Subtract 2x from both sides to get: x² - 2x + 1 > 4
Factor left side to get: (x - 1)² > 4
Now test each answer choice...
(A) –5
If x = -5, we get: (-5 - 1)² > 4
Simplify: (-6)² > 4
Simplify: 36 > 4
Works!!!
(B) –3
If x = –3, we get: (–3 - 1)² > 4
Simplify: (-4)² > 4
Simplify: 16 > 4
Works!!!
(C) 0
If x = 0, we get: (0 - 1)² > 4
Simplify: (-1)² > 4
Simplify: 1 > 4
DOESN'T WORK
Answer: C
Cheers,
Brent
Re: If (x + 1)^2 – 2x > 2(x + 1) + 2, then x cannot equal
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23 Aug 2019, 10:42
23 Aug 2019, 10:42
1
Hi Carcass, Substituting the value of option D)3 will yield 10>10, even that should be the answer right?
