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The center of the circle is O

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NailItGre
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The center of the circle is O [#permalink] New post   Updated on: 16 Nov 2019, 02:30
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#greprepclub The center of the circle is O.jpg [ 12.69 KiB | Viewed 13608 times ]



The center of the circle is O, and RS = ST = 4. What is the length of arc RWT?

A. \(\frac{4\pi}{3}\)

B. \(\frac{8\pi}{3}\)

C. \(\frac{16\pi}{3}\)

D. \(4\pi\)

E. \(8\pi\)
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C

Originally posted by NailItGre on 02 Oct 2019, 20:40.
Last edited by Carcass on 16 Nov 2019, 02:30, edited 3 times in total.
Edited by Carcass
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Re: The center of the circle is O [#permalink] New post   03 Oct 2019, 04:18
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Option C

OA plz
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Re: The center of the circle is O [#permalink] New post   03 Oct 2019, 05:37
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NailItGre wrote:
Attachment:
The attachment #greprepclub The center of the circle is O.jpg is no longer available



The center of the circle is O, and RS = ST = 4. What is the length of arc RWT?

A. \(\frac{4\pi}{3}\)

B. \(\frac{8\pi}{3}\)

C. \(\frac{16\pi}{3}\)

D. \(4\pi\)

E. \(8\pi\)


Here,

RS = ST = 4

Therefore TO = RO = 4

Hence \(\triangle\) STO = \(\triangle\)SRO = Equilateral \(\triangle\)

The \(\angle\)TOR =120

ARC TWR = \(2\pi * Radius * \frac{240}{360} = 2\pi * 4 *\frac{240}{360} = \frac{16\pi}{3}\)
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anoop1995
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Re: The center of the circle is O [#permalink] New post   16 Nov 2019, 00:20
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How do you consider OT = RO = 4? Please could you explain detailedly ?

pranab01 wrote:
NailItGre wrote:
Attachment:
#greprepclub The center of the circle is O.jpg



The center of the circle is O, and RS = ST = 4. What is the length of arc RWT?

A. \(\frac{4\pi}{3}\)

B. \(\frac{8\pi}{3}\)

C. \(\frac{16\pi}{3}\)

D. \(4\pi\)

E. \(8\pi\)


Here,

RS = ST = 4

Therefore TO = RO = 4

Hence \(\triangle\) STO = \(\triangle\)SRO = Equilateral \(\triangle\)

The \(\angle\)TOR =120

ARC TWR = \(2\pi * Radius * \frac{240}{360} = 2\pi * 4 *\frac{240}{360} = \frac{16\pi}{3}\)
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The center of the circle is 0, and RS = ST = 4. What is the [#permalink] New post   21 Nov 2019, 10:33
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Attachment:
#greprepclub The center of the circle is 0.jpg
#greprepclub The center of the circle is 0.jpg [ 19.91 KiB | Viewed 12133 times ]


The center of the circle is 0, and \(RS = ST = 4\). What is the length of arc \(RWT\)?


A. \(\frac{4 \pi}{3}\)

B. \(\frac{8 \pi}{3}\)

C. \(\frac{16 \pi}{3}\)

D. \(4 \pi\)

E. \(8 \pi\)


Kudos for the right answer and solution.
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Re: The center of the circle is 0, and RS = ST = 4. What is the [#permalink] New post   07 May 2020, 08:27
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Carcass wrote:
Attachment:
#greprepclub The center of the circle is 0.jpg


The center of the circle is 0, and \(RS = ST = 4\). What is the length of arc \(RWT\)?


A. \(\frac{4 \pi}{3}\)

B. \(\frac{8 \pi}{3}\)

C. \(\frac{16 \pi}{3}\)

D. \(4 \pi\)

E. \(8 \pi\)


Kudos for the right answer and solution.



This is explained {HERE}
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Re: The center of the circle is O [#permalink] New post   07 May 2020, 10:45
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Thank you. Merged similar topics.

You could do this also. :roll: :wink:
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Re: The center of the circle is O [#permalink] New post   07 May 2020, 19:31
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pranab223 wrote:
NailItGre wrote:
Attachment:
#greprepclub The center of the circle is O.jpg



The center of the circle is O, and RS = ST = 4. What is the length of arc RWT?

A. \(\frac{4\pi}{3}\)

B. \(\frac{8\pi}{3}\)

C. \(\frac{16\pi}{3}\)

D. \(4\pi\)

E. \(8\pi\)


Here,

RS = ST = 4

Therefore TO = RO = 4

Hence \(\triangle\) STO = \(\triangle\)SRO = Equilateral \(\triangle\)

The \(\angle\)TOR =120

ARC TWR = \(2\pi * Radius * \frac{240}{360} = 2\pi * 4 *\frac{240}{360} = \frac{16\pi}{3}\)



How TO=RO=4; I didn't get this point, please elaborate
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Re: The center of the circle is O [#permalink] New post   28 Sep 2020, 17:12
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vndnjn wrote:


How TO=RO=4; I didn't get this point, please elaborate


Yes this needs explanation plz. I assume that circle has equilateral triangle and all sides are equal in equilateral triangle therefore radius is 4.
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Re: The center of the circle is O [#permalink] New post   19 Sep 2023, 18:43
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Re: The center of the circle is O [#permalink]
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