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y is greater equal 2
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16 Jan 2020, 10:18
16 Jan 2020, 10:18
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69% (01:14) correct
30% (01:22) wrong based on 157 sessions
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\(y \geq 2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(\frac{y!}{5(y-2)!}\) |
\(\frac{(y+1)!}{3(y-1)!}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: y is greater equal 2
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16 Jan 2020, 12:35
16 Jan 2020, 12:35
2
We need to take values for this questions.
1. y = 2
Option A: \(\frac{y!}{5(y-2)!} = \frac{2!}{5 \times 0!} = \frac{2}{5} = 0.4\)
Option B: \(\frac{(y+1)!}{3(y-1)!} = \frac{3!}{3 \times 2!} = \frac{6}{6} = 1\)
Option A < Option B
2. y = 5
Option A: \(\frac{y!}{5(y-2)!} = \frac{5!}{5 \times 3!} = \frac{120}{30} = 4\)
Option B: \(\frac{(y+1)!}{3(y-1)!} = \frac{6!}{3 \times 4!} = \frac{720}{72} = 10\)
Option A < Option B
We can see that as we keep increasing the value of y, the gap between Option A and Option B will keep increasing and Option A will always be smaller than Option B.
OA, B
1. y = 2
Option A: \(\frac{y!}{5(y-2)!} = \frac{2!}{5 \times 0!} = \frac{2}{5} = 0.4\)
Option B: \(\frac{(y+1)!}{3(y-1)!} = \frac{3!}{3 \times 2!} = \frac{6}{6} = 1\)
Option A < Option B
2. y = 5
Option A: \(\frac{y!}{5(y-2)!} = \frac{5!}{5 \times 3!} = \frac{120}{30} = 4\)
Option B: \(\frac{(y+1)!}{3(y-1)!} = \frac{6!}{3 \times 4!} = \frac{720}{72} = 10\)
Option A < Option B
We can see that as we keep increasing the value of y, the gap between Option A and Option B will keep increasing and Option A will always be smaller than Option B.
OA, B
Carcass wrote:
\(y \geq 2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(\frac{y!}{5(y-2)!}\) |
\(\frac{(y+1)!}{3(y-1)!}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: y is greater equal 2
[#permalink]
16 Jan 2020, 12:37
16 Jan 2020, 12:37
Carcass wrote:
\(y \geq 2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(\frac{y!}{5(y-2)!}\) |
\(\frac{(y+1)!}{3(y-1)!}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
If I were to plug in 2, I believe A becomes undefined whereas B becomes 1. In this particular case, would B be considered bigger? I am not sure how to compare a number against an undefined
