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(3^-1+3^-2)

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Carcass
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(3^-1+3^-2) [#permalink] New post   23 Mar 2020, 03:31
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Quantity A
Quantity B
\((3^{-1}+3^{-2})^{-1}\)
\(1\)




A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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A
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sukrut96
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Re: (3^-1+3^-2) [#permalink] New post   Updated on: 23 Mar 2020, 21:29
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Take 3^-1 common, thus, we get 3^-1(1+3^-1)
on solving this, 1/3(1+1/3). Multiply By 3 to get (1+1/3) and thus, option B becomes 3.
On solving A, we get 4/3 = 1.3, which is less than B, which is 3.
Thus option B should be correct.

Originally posted by sukrut96 on 23 Mar 2020, 04:04.
Last edited by sukrut96 on 23 Mar 2020, 21:29, edited 2 times in total.
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Re: (3^-1+3^-2) [#permalink] New post   23 Mar 2020, 12:04
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The wrong solution. 4/3*1/3 = 4/9 - less than 1
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Re: (3^-1+3^-2) [#permalink] New post   23 Mar 2020, 21:31
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DeadDemon wrote:
The wrong solution. 4/3*1/3 = 4/9 - less than 1

Nice catch, I have updated my answer.
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Re: (3^-1+3^-2) [#permalink] New post   27 Mar 2020, 12:06
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DeadDemon wrote:
The wrong solution. 4/3*1/3 = 4/9 - less than 1

So, the and would be B? or it still remains A ?
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Re: (3^-1+3^-2) [#permalink] New post   27 Mar 2020, 12:25
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Sorry folks

there was a typo on the first quantity due to the latex code that did not show up

The first quantity is raised to minus one

The first quantity is \(\frac{4}{9}\) but raised to minus one becomes \(\frac{9}{4}\)

Which clearly is > 1

A is the answer
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Re: (3^-1+3^-2) [#permalink] New post   27 Mar 2020, 12:34
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Carcass wrote:
Sorry folks

there was a typo on the first quantity due to the latex code that did not show up

The first quantity is raised to minus one

The first quantity is \(\frac{4}{9}\) but raised to minus one becomes \(\frac{9}{4}\)

Which clearly is > 1

A is the answer

thank you!
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Re: (3^-1+3^-2) [#permalink] New post   28 Mar 2020, 14:09
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Carcass wrote:
Quantity A
Quantity B
\((3^{-1}+3^{-2})^{-1}\)
\(1\)




A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation


3^-1 = 1/3
3^-2 = 1/3^2 = 1/9

1/3 + 1/9 = 3/9 + 1/9 = (4/9)^-1 = 9/4 > 1 So answer choice choice A
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Re: (3^-1+3^-2) [#permalink]
28 Mar 2020, 14:09
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