GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In rectangle A, the ratio of the length to the width is 3: 1
[#permalink]
07 Aug 2020, 09:21
07 Aug 2020, 09:21
1
1
Expert Reply
8
Bookmarks
00:00
Question Stats:
63% (02:33) correct
36% (02:45) wrong based on 122 sessions
Hide Show timer Statistics
In rectangle A, the ratio of the length to the width is 3: 1. In rectangle B, the ratio of the length to the width is 4: 1. The area of rectangle A is 27 percent of the area of rectangle B. The perimeter of rectangle A is v percent of the perimeter of rectangle B.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
Kudos for the right solution and explanation
Quantity A |
Quantity B |
\(v\) |
\(54\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
Kudos for the right solution and explanation
Re: In rectangle A, the ratio of the length to the width is 3: 1
[#permalink]
08 Aug 2020, 07:08
08 Aug 2020, 07:08
6
2
Bookmarks
A:
area = 3x * 1x =3x^2
perimeter = 2(3x + x) = 8x
B:
area = 4y * y = 4y^2
perimeter = 2(4y + y) = 10y
to find x/y:
area of B * 0.27 = area of A
4y^2 * 0.27 = 3x^2
x/y = 3/5
to find v:
perimeter of B * v/100 = perimeter of A
10y * v/100 = 8x
v = 80 * (x/y)
v = 48.
area = 3x * 1x =3x^2
perimeter = 2(3x + x) = 8x
B:
area = 4y * y = 4y^2
perimeter = 2(4y + y) = 10y
to find x/y:
area of B * 0.27 = area of A
4y^2 * 0.27 = 3x^2
x/y = 3/5
to find v:
perimeter of B * v/100 = perimeter of A
10y * v/100 = 8x
v = 80 * (x/y)
v = 48.
General Discussion
Re: In rectangle A, the ratio of the length to the width is 3: 1
[#permalink]
08 Aug 2020, 03:47
08 Aug 2020, 03:47
2
Consider the sides of Rectangle A as 3x and 1x, then area is 3x² and perimeter is 4x
sides of Rectangle B as 4y and 1y, then area is 4y² and perimeter is 5x
1) => 3x²= (27/100)* 4y²
2) => 4x = (v/100) *5y
From statement 1
x=(3/5)y
substitute x value in statement 2
4 *(3/5)y= (v/100)*5y
v=48
Hence the answer is B
sides of Rectangle B as 4y and 1y, then area is 4y² and perimeter is 5x
1) => 3x²= (27/100)* 4y²
2) => 4x = (v/100) *5y
From statement 1
x=(3/5)y
substitute x value in statement 2
4 *(3/5)y= (v/100)*5y
v=48
Hence the answer is B
