Last visit was: 18 Dec 2024, 08:10 It is currently 18 Dec 2024, 08:10

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30355
Own Kudos [?]: 36751 [3]
Given Kudos: 26080
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 30355
Own Kudos [?]: 36751 [0]
Given Kudos: 26080
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12226 [3]
Given Kudos: 136
Send PM
avatar
Intern
Intern
Joined: 02 Sep 2020
Posts: 14
Own Kudos [?]: 9 [0]
Given Kudos: 0
Send PM
Re: From a group of 8 volunteers, including Andrew and Karen, 4 [#permalink]
GreenlightTestPrep wrote:
Carcass wrote:
From a group of 8 volunteers, including Andrew and Karen, 4 people are to be selected at random to organize a charity event. What is the probability that Andrew will be among the 4 volunteers selected and Karen will not?

A. 3/7
B. 5/12
C. 27/70
D. 2/7
E. 9/35


P(Andrew is selected but Karen is not selected) = (number of 4-person groups with Andrew but not Karen)/(total # of 4-person groups possible)

number of 4-person groups with Andrew but not Karen
Take the task of creating groups and break it into stages.

Stage 1: Place Andrew in the 4-person group
We can complete this stage in 1 way

Stage 2: Send Karen out of the room and, from the remaining 6 volunteers, select 3 more people.
Since the order in which we select the 3 volunteers does not matter, we can use combinations.
We can select 3 people from 6 volunteers in 6C3 ways (20 ways).

the video below shows you how to calculate combinations (like 6C3) in your head

By the Fundamental Counting Principle (FCP), we can complete the 2 stages (and thus create a 4-person group) in (1)(20) ways (= 20 ways)

total # of 4-person groups possible
We can select 4 people from all 8 volunteers in 8C4 ways ( = 70 ways).

So, P(Andrew is selected but Karen is not selected) = (20)/(70)
= 2/7

Answer: D

Cheers,
Brent



Hi Brent,

Shouldnt probability of choosing Andrew be 1/8?How come we are assuming it to be 1?

From my understanding,it should be 1/8 x 6c3 divided by 8c4.Not sure how we are taking "1" for Andrew's selection
avatar
Intern
Intern
Joined: 06 Aug 2020
Posts: 13
Own Kudos [?]: 11 [0]
Given Kudos: 0
Send PM
Re: From a group of 8 volunteers, including Andrew and Karen, 4 [#permalink]
vaishar3 wrote:

Hi Brent,

Shouldnt probability of choosing Andrew be 1/8?How come we are assuming it to be 1?

From my understanding,it should be 1/8 x 6c3 divided by 8c4.Not sure how we are taking "1" for Andrew's selection


I had the same concern - it's not guaranteed that Andrew will be selected, right?
avatar
Intern
Intern
Joined: 12 Sep 2020
Posts: 15
Own Kudos [?]: 9 [0]
Given Kudos: 0
Send PM
Re: From a group of 8 volunteers, including Andrew and Karen, 4 [#permalink]
3
jaidevphadke wrote:
vaishar3 wrote:

Hi Brent,

Shouldnt probability of choosing Andrew be 1/8?How come we are assuming it to be 1?

From my understanding,it should be 1/8 x 6c3 divided by 8c4.Not sure how we are taking "1" for Andrew's selection


I had the same concern - it's not guaranteed that Andrew will be selected, right?



You cannot keep one thing probabilistic and one thing fixed. If you take probability of choosing Andrew, then you need to multiply by the probability of not choosing Karen. And the probabilty of not choosing Karen is not 6c3. The probability of not choosing Karen is 6/7 * 5/6 * 4/5. Therefore your total probability comes to 1/14.

But then you assumed that Andrew will be the first person to be selected. What if he is the last person to be selected? Therefore you need to multiply it by 4, since Andrew can be selected in any one of the 4 slots. So total is 1/14 * 4 = 2/7
Manager
Manager
Joined: 25 Aug 2020
Posts: 80
Own Kudos [?]: 67 [2]
Given Kudos: 65
Send PM
Re: From a group of 8 volunteers, including Andrew and Karen, 4 [#permalink]
2
(1) The ratio Andrew is selected in the end = 4/8 = 1/2

(2) The ratio Karen is selected= 3/7
(3) -> The ration Karen is not selected = 1-3/7 = 4/7

(1) x (3) = 1/2 * 4/7 = 2/7

So answer is (D)
Prep Club for GRE Bot
Re: From a group of 8 volunteers, including Andrew and Karen, 4 [#permalink]
Moderators:
GRE Instructor
88 posts
GRE Forum Moderator
37 posts
Moderator
1115 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne