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On Monday, a person mailed 8 packages weighing an average (a
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09 Sep 2020, 10:52
09 Sep 2020, 10:52
Expert Reply
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Question Stats:
95% (01:35) correct
4% (03:30) wrong based on 22 sessions
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On Monday, a person mailed 8 packages weighing an average (arithmetic mean) of \(12\frac{3}{8}\) pounds, and on Tuesday, 4 packages weighing an average of \(15\frac{1}{4}\) pounds. What was the average weight, in pounds, of all the packages the person mailed on both days?
(A) \(13\frac{1}{3}\)
(B) \(13\frac{13}{16}\)
(C) \(15\frac{1}{2}\)
(D) \(15\frac{15}{16}\)
(E) \(16\frac{1}{2}\)
(A) \(13\frac{1}{3}\)
(B) \(13\frac{13}{16}\)
(C) \(15\frac{1}{2}\)
(D) \(15\frac{15}{16}\)
(E) \(16\frac{1}{2}\)
Re: On Monday, a person mailed 8 packages weighing an average (a
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10 Sep 2020, 04:19
10 Sep 2020, 04:19
1
[8*(99/8) + 4*(61/4)] / 12 = 40/3 (A)
Re: On Monday, a person mailed 8 packages weighing an average (a
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13 Sep 2020, 01:45
13 Sep 2020, 01:45
1
total weight of first 8 packages = 99 pounds
total wight of next 4 packages =61
total weight of 12 packages =160
average weight of 12 packages that he mailed is =160/12= 40/3
answer A is correct
"if you like the explanation please press kudos please"
total wight of next 4 packages =61
total weight of 12 packages =160
average weight of 12 packages that he mailed is =160/12= 40/3
answer A is correct
"if you like the explanation please press kudos please"
