Re: If n is a positive integer such that the units (ones)
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22 Mar 2025, 05:15
n^2 + 4n has units digit ending with 7 i.e. it is odd. Since 4n has to even, n^2 and therefore n are odd numbers.
N's unit digit could end in 1,3,5 or 9 (Since the question states that the unit digit of n is not 7).
On trial and error basis, we find that for n = 9 in the units digit, n^2 + 4n returns 7 in the units digit.
Therefore, n +3 (9+3,19+3,29+3...) will return 2 in the units digit