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Re: If n is a positive integer such that the units (ones) [#permalink]
Carcass after simplyfying n(n+4) how we solve for the units digit
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Re: If n is a positive integer such that the units (ones) [#permalink]
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We can note that for n with 7 or 9 as unit digit, n^2 + 4n will have 7 at units digit. But, the units digit of n is not 7. Hence, units digit of n has to be 9.
Then, units digit of n+3 is 2.
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Re: If n is a positive integer such that the units (ones) [#permalink]
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n^2 + 4n has units digit ending with 7 i.e. it is odd. Since 4n has to even, n^2 and therefore n are odd numbers.

N's unit digit could end in 1,3,5 or 9 (Since the question states that the unit digit of n is not 7).

On trial and error basis, we find that for n = 9 in the units digit, n^2 + 4n returns 7 in the units digit.

Therefore, n +3 (9+3,19+3,29+3...) will return 2 in the units digit
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Re: If n is a positive integer such that the units (ones) [#permalink]
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