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(x+5)^2 - (y-3)^2 = 0 and x +y =2
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Updated on: 14 Oct 2020, 13:13
Updated on: 14 Oct 2020, 13:13
6
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Question Stats:
82% (01:57) correct
17% (03:01) wrong based on 80 sessions
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\((x+5)^2 - (y-3)^2=0\)
\(x + y = 2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(x + y = 2\)
Quantity A |
Quantity B |
\(x-\)y |
\(0\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Originally posted by whollymoses on 14 Oct 2020, 11:05.
Last edited by Carcass on 14 Oct 2020, 13:13, edited 1 time in total.
Last edited by Carcass on 14 Oct 2020, 13:13, edited 1 time in total.
Edited by Carcass
Re: (x+5)^2 - (y-3)^2 = 0 and x +y =2
[#permalink]
17 Oct 2020, 06:18
17 Oct 2020, 06:18
6
Quote:
\((x+5)^2−(y−3)^2\)=0
Step 1: Understanding the question
The equation is in the form of \(a^2 - b^2\) = (a+b) (a-b)
Step 2: Calculation
(x+5 + y−3) (x+5-y +3) =0
(x+y+2) (x-y+8) = 0
(2+2) (x-y+8) = 0
4(x-y+8) = 0
hence, x-y = -8
B is correct
General Discussion
Re: (x+5)^2 - (y-3)^2 = 0 and x +y =2
[#permalink]
14 Oct 2020, 13:14
14 Oct 2020, 13:14
Expert Reply
Please Sir, see how to format a QCQ properly and the use of the timer. It will take one minutes to post a question in the right manner
https://gre.myprepclub.com/forum/how-to-po ... 12752.html
Thank you for your collaboration
Regards
https://gre.myprepclub.com/forum/how-to-po ... 12752.html
Thank you for your collaboration
Regards
