GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A total of 125 cubes are present. They are stacked in layers
[#permalink]
27 Jun 2021, 11:02
27 Jun 2021, 11:02
2
00:00
Question Stats:
12% (02:10) correct
87% (01:47) wrong based on 24 sessions
Hide Show timer Statistics
A total of 125 cubes, each 2 inches on an edge, are stacked in layers to form a large solid cube. What is the surface area in square inches of the large cube?
A. 200
B. 500
C. 600
D. 1500
E. 3000
A. 200
B. 500
C. 600
D. 1500
E. 3000
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: A total of 125 cubes are present. They are stacked in layers
[#permalink]
29 Jun 2021, 09:58
29 Jun 2021, 09:58
2
axeus25 wrote:
A total of 125 cubes, each 2 inches on an edge, are stacked in layers to form a large solid cube. What is the surface area in square inches of the large cube?
A. 200
B. 500
C. 600
D. 1500
E. 3000
A. 200
B. 500
C. 600
D. 1500
E. 3000
Volume of each small cube = \(2^3 = 8in^3\)
Volume of 125 small cubes = \(125 (8) = 1000in^3\)
So, side of larger cube with volume \(1000in^3\), is \(10in\)
Total Surface Area of larger cube \(= 6a^2 = 600in^2\)
The answer should be C???
Re: A total of 125 cubes are present. They are stacked in layers
[#permalink]
29 Jun 2021, 22:40
29 Jun 2021, 22:40
Yes the answer should be C.
