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E is the sum of the first 40 positive even integers. K is the sum o
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03 Aug 2021, 06:26
03 Aug 2021, 06:26
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E is the sum of the first 40 positive even integers. K is the sum of the first 40 positive odd integers.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
E-K |
40 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: E is the sum of the first 40 positive even integers. K is the sum o
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03 Aug 2021, 07:04
03 Aug 2021, 07:04
1
Ans C
E = sum of even 40 numbers = 40*41
K = sum of odd 40 odd no. = 40 * 40
E - k = 40
E = sum of even 40 numbers = 40*41
K = sum of odd 40 odd no. = 40 * 40
E - k = 40
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E is the sum of the first 40 positive even integers. K is the sum o
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03 Aug 2021, 07:13
03 Aug 2021, 07:13
1
Carcass wrote:
E is the sum of the first 40 positive even integers. K is the sum of the first 40 positive odd integers.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
E-K |
40 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Remember:
1. Average of \(n\) consecutive even numbers is \((n + 1)\)
2. Average of \(n\) consecutive odd numbers is \(n\)
Sum = (Average)(number of terms)
E = \((40 + 1)40 = (41)40\)
K = \((40)40\)
Col. A: \(40(41 - 40) = 40\)
Col. B: \(40\)
Hence, option C
