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The average (arithmetic mean) of the integers from 100 to 500, inclusi

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The average (arithmetic mean) of the integers from 100 to 500, inclusi [#permalink] New post   11 Aug 2021, 01:21
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The average (arithmetic mean) of the integers from 100 to 500, inclusive, is how much greater than the average of the integers from 10 to 50, inclusive?

(A) 450
(B) 300
(C) 270
(D) 250
(E) 90
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C
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Re: The average (arithmetic mean) of the integers from 100 to 500, inclusi [#permalink] New post   11 Aug 2021, 01:54
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The average of consecutive integers in an arithermatic progression is given by (first number+last number)/2

So (100+500)/2=300 and (10+50)/2=60

Difference of which is 300-30=270. The answer is C
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Re: The average (arithmetic mean) of the integers from 100 to 500, inclusi [#permalink] New post   03 Aug 2022, 22:33
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Theory

    ➡ In Case of consecutive numbers Mean = Mean of First term and Last Term

The average (arithmetic mean) of the integers from 100 to 500, inclusive

Average from 100 to 500 = \(\frac{100+500}{2}\) = \(\frac{600}{2}\) = 300

The average of the integers from 10 to 50, inclusive

Average from 10 to 50 = \(\frac{10+50}{2}\) = \(\frac{60}{2}\) = 30

Difference of the two Averages = Average from 100 to 500 - Average from 10 to 50 = 300 - 30 = 270

So, Answer will be C.
Hope it helps!

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Re: The average (arithmetic mean) of the integers from 100 to 500, inclusi [#permalink]
03 Aug 2022, 22:33
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