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A line with slope -4 passes through (x,4) and (-2,8)
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14 Sep 2021, 08:11
14 Sep 2021, 08:11
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Question Stats:
85% (01:00) correct
14% (00:47) wrong based on 7 sessions
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If a line with slope -4 passes through (x,4) and (-2,8), what could be the value of x?
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Re: A line with slope -4 passes through (x,4) and (-2,8)
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14 Sep 2021, 09:42
14 Sep 2021, 09:42
1
Answer:-1
Bcz
Use slope formula i.e.
M=(y2-y1)/(x2-x1)
Plug in values
-4=(8-4)/(-2-x)
Solving above yields
x=-1
Posted from my mobile device
Bcz
Use slope formula i.e.
M=(y2-y1)/(x2-x1)
Plug in values
-4=(8-4)/(-2-x)
Solving above yields
x=-1
Posted from my mobile device
A line with slope -4 passes through (x,4) and (-2,8)
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15 Sep 2021, 14:45
15 Sep 2021, 14:45
1
A line with slope -4 passes through points A(x,4) and B (-2,8)
Let the line eqn be y=-4x+c
putting Point A in eqn as it lies on line must satisfy eqn: 4=-4x+c --(1)
putting Point B in eqn as it lies on line must satisfy eqn: 8=8+c=>c=0
thus eqn(2) becomes -4x+0=4=> x=-1
Let the line eqn be y=-4x+c
putting Point A in eqn as it lies on line must satisfy eqn: 4=-4x+c --(1)
putting Point B in eqn as it lies on line must satisfy eqn: 8=8+c=>c=0
thus eqn(2) becomes -4x+0=4=> x=-1
