GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In a certain apartment building, there are one-bedroom and two-bedroom
[#permalink]
16 Sep 2021, 09:41
16 Sep 2021, 09:41
Expert Reply
7
Bookmarks
00:00
Question Stats:
61% (02:58) correct
38% (02:31) wrong based on 26 sessions
Hide Show timer Statistics
In a certain apartment building, there are one-bedroom and two-bedroom apartments. The rental prices of the apartment depend on a number of factors, but on average, two-bedroom apartments have higher rental prices than do one-bedroom apartments. Let R be the average rental price for all apartments in the building. If R is $5,600 higher than the average rental price for all one-bedroom apartments, and if the average rental price for all two-bedroom apartments is $10,400 higher that R, then what percentage of apartments in the building are two-bedroom apartments?
(A) 26%
(B) 35%
(C) 39%
(D) 42%
(E) 52%
(A) 26%
(B) 35%
(C) 39%
(D) 42%
(E) 52%
Re: In a certain apartment building, there are one-bedroom and two-bedroom
[#permalink]
16 Sep 2021, 19:40
16 Sep 2021, 19:40
7
1
Bookmarks
We have one bedroom & two-bedroom apartment.
Let's say the no of one bedroom apt \(= x\) & two bedroom apt \(= y\)
& avg of one bedroom apt \(= a\) & avg of two bedroom \(= b\)
R is the average rental price for all apartments in the building. If R is $5,600 higher than the average rental price for all one-bedroom apartments, and if the average rental price for all two-bedroom apartments is $10,400 higher than R
\(R = a + 5600\) & \(b = R + 10400\)
Average Rent \(R = \frac{xa + yb}{x + y}\)
\(R = \frac{x(R - 5600) + y(R + 10400)}{x + y}\)
\(Rx+Ry = Rx - 5600x + Ry + 10400y\)
\(5600x = 10400y\)
\(\frac{y}{x} = \frac{7}{13}\)
2 bedroom apt \(= \frac{7}{20} = 35\)%
Answer B
Let's say the no of one bedroom apt \(= x\) & two bedroom apt \(= y\)
& avg of one bedroom apt \(= a\) & avg of two bedroom \(= b\)
R is the average rental price for all apartments in the building. If R is $5,600 higher than the average rental price for all one-bedroom apartments, and if the average rental price for all two-bedroom apartments is $10,400 higher than R
\(R = a + 5600\) & \(b = R + 10400\)
Average Rent \(R = \frac{xa + yb}{x + y}\)
\(R = \frac{x(R - 5600) + y(R + 10400)}{x + y}\)
\(Rx+Ry = Rx - 5600x + Ry + 10400y\)
\(5600x = 10400y\)
\(\frac{y}{x} = \frac{7}{13}\)
2 bedroom apt \(= \frac{7}{20} = 35\)%
Answer B
General Discussion
Re: In a certain apartment building, there are one-bedroom and two-bedroom
[#permalink]
21 Oct 2025, 17:07
21 Oct 2025, 17:07
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
