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Which of the following is the median of the terms:
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17 Jul 2023, 23:07
17 Jul 2023, 23:07
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Which of the following is the median of the terms:
\(\frac{3}{2},\frac{3.03}{2.02},\frac{3}{2.02},\dfrac{\sqrt{9.09}}{\sqrt{4.04}},\frac{9.09}{2},\frac{3}{4.04}\)
A. 1.52
B. 1.51
C. 1.50
D. 1.49
E. 1.48
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\(\frac{3}{2},\frac{3.03}{2.02},\frac{3}{2.02},\dfrac{\sqrt{9.09}}{\sqrt{4.04}},\frac{9.09}{2},\frac{3}{4.04}\)
A. 1.52
B. 1.51
C. 1.50
D. 1.49
E. 1.48
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE NUMBER PROPERTIES
Re: Which of the following is the median of the terms:
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18 Jul 2023, 11:29
18 Jul 2023, 11:29
1
First of all arrange all the numbers in ascending order:
3/4.04 = 0.74, 3/2.02 = 1.48, 3/2 = 1.5, 3.03/2.02 = 1.5, √9.09/√4.04 = 1.5, 9.09/2 = 4.545
Here, n=6, thus, we use the median for even number of observations formula :
{(n/2)th term + [(n/2)+1]th term}/2
Therefore, (3rd term + 4th term) / 2 = (1.5+1.5) / 2 = 1.5
Hence, the answer is C) 1.50
3/4.04 = 0.74, 3/2.02 = 1.48, 3/2 = 1.5, 3.03/2.02 = 1.5, √9.09/√4.04 = 1.5, 9.09/2 = 4.545
Here, n=6, thus, we use the median for even number of observations formula :
{(n/2)th term + [(n/2)+1]th term}/2
Therefore, (3rd term + 4th term) / 2 = (1.5+1.5) / 2 = 1.5
Hence, the answer is C) 1.50
Re: Which of the following is the median of the terms:
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15 Oct 2023, 02:32
15 Oct 2023, 02:32
1
Don’t waste your time to calculate all fractions. We have an even set of six numbers, hence the median is the average of the third and fourth value listed in ascending order.
Notice that we have a mix of proper and improper fractions. Proper fractions are always smaller than improper fractions. Hence, 3/4.04 and 3/2.02 are the two smallest fractions.
We only have to find the third and fourth largest fractions among the improper fractions. Without calculating we see that third, fourth, and fifth have the same value. Hence, the median is 1.50.
Answer C
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Notice that we have a mix of proper and improper fractions. Proper fractions are always smaller than improper fractions. Hence, 3/4.04 and 3/2.02 are the two smallest fractions.
We only have to find the third and fourth largest fractions among the improper fractions. Without calculating we see that third, fourth, and fifth have the same value. Hence, the median is 1.50.
Answer C
Posted from my mobile device
