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sqrt3 80 + 3/9+
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10 Sep 2023, 10:06
10 Sep 2023, 10:06
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Question Stats:
75% (02:37) correct
25% (03:22) wrong based on 16 sessions
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\(\sqrt{3 \sqrt{80} + \frac{3}{9+ 4 \sqrt{5}} }\)
A. \(3\)
B. \(3 \sqrt{2}\)
C. \(2 \sqrt{3}\)
D. \(3 \sqrt{3}\)
E. \(4 \sqrt{3}\)
A. \(3\)
B. \(3 \sqrt{2}\)
C. \(2 \sqrt{3}\)
D. \(3 \sqrt{3}\)
E. \(4 \sqrt{3}\)
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: sqrt3 80 + 3/9+
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11 Sep 2023, 09:53
11 Sep 2023, 09:53
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first element can be rewrtitten as:4*sqrt(80)= 12sqrt(5),
second element can be rationalized obtaining : 3(9-4sqrt(5))/(9^2-(16*5))
summing them : 12sqrt(5) + (27-12sqrt(5))/1 , which is 27
sqrt(27)=3*sqrt(3)
second element can be rationalized obtaining : 3(9-4sqrt(5))/(9^2-(16*5))
summing them : 12sqrt(5) + (27-12sqrt(5))/1 , which is 27
sqrt(27)=3*sqrt(3)
Re: sqrt3 80 + 3/9+
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15 Sep 2023, 14:35
15 Sep 2023, 14:35
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3 root 80 = 12 root 5
3/(9+4 root 5) can be simplified to (3 * (9-4 root 5))/(9+4 root 5)(9-4 root 5) = 27 - 12 root 5 / 81-80 = 27 - 12 root 5
12 root 5 + 27 - 12 root 5 = 27
root 27 = 3 root 3
Choice D
3/(9+4 root 5) can be simplified to (3 * (9-4 root 5))/(9+4 root 5)(9-4 root 5) = 27 - 12 root 5 / 81-80 = 27 - 12 root 5
12 root 5 + 27 - 12 root 5 = 27
root 27 = 3 root 3
Choice D
