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xy > 0 and y < 1
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19 Dec 2023, 05:53
19 Dec 2023, 05:53
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63% (01:54) correct
36% (01:12) wrong based on 11 sessions
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xy > 0 and y < −1
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x/y |
xy |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: xy > 0 and y < 1
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21 Dec 2023, 16:30
21 Dec 2023, 16:30
1
Since y < -1, x must be less than 0 in order for xy > 0.
Let's say y = -2 and x = -1, and plug in for the expressions in Quantity A and B.
xy = (-1)(-2) = 2
x/y = (-1)/(-2) = 1/2
2 > 1/2, so xy > x/y
To check whether the comparison changes when x = y, let's say both y and x = -2.
xy = 4
x/y = 1
xy is still > x/y.
Let's say y = -2 and x = -1, and plug in for the expressions in Quantity A and B.
xy = (-1)(-2) = 2
x/y = (-1)/(-2) = 1/2
2 > 1/2, so xy > x/y
To check whether the comparison changes when x = y, let's say both y and x = -2.
xy = 4
x/y = 1
xy is still > x/y.
Re: xy > 0 and y < 1
[#permalink]
31 Dec 2023, 01:33
31 Dec 2023, 01:33
1
I'm confused - the question doesn't mention X is an integer.
In case x=y=-1/2
QtA
(-1/2)/(-1/2)= 1
QtB
(-1/2)*(-1/2)= 1/4
In this case, Qt A is bigger than QtB so the answer should be D.
@caracass - would love your input here.
In case x=y=-1/2
QtA
(-1/2)/(-1/2)= 1
QtB
(-1/2)*(-1/2)= 1/4
In this case, Qt A is bigger than QtB so the answer should be D.
@caracass - would love your input here.
