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A widow received 1/3 of her husband's estate, and each of he
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27 Mar 2018, 21:55
27 Mar 2018, 21:55
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Question Stats:
67% (01:38) correct
32% (01:42) wrong based on 37 sessions
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A widow received \(\frac{1}{3}\) of her husband's estate, and each of her three sons received \(\frac{1}{3}\) of the balance. If the widow and one of her sons received a total of \($120,000\), what was the amount of the estate?
A) $180,000
B) $192,000
C) $216,000
D) $270,000
E) $275,000
A) $180,000
B) $192,000
C) $216,000
D) $270,000
E) $275,000
Re: A widow received 1/3 of her husband's estate, and each of he
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28 Mar 2018, 12:20
28 Mar 2018, 12:20
Expert Reply
I do not know if the answer are precise. However, we could reach the solution as well because the values are fairly apart and not tight.
Now, the widow had 1/3, and 3 sons 1/3 of the rest (balance). So, the widow had 1/3 and each son 1/3 divided by 3 or 2/9.
1/3 + 2/9 = roughly 0.55%.
120,000 = 0.55% of X
C is the answer
Now, the widow had 1/3, and 3 sons 1/3 of the rest (balance). So, the widow had 1/3 and each son 1/3 divided by 3 or 2/9.
1/3 + 2/9 = roughly 0.55%.
120,000 = 0.55% of X
C is the answer
Re: A widow received 1/3 of her husband's estate, and each of he
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14 Dec 2018, 09:54
14 Dec 2018, 09:54
2
Carcass wrote:
I do not know if the answer are precise. However, we could reach the solution as well because the values are fairly apart and not tight.
Now, the widow had 1/3, and 3 sons 1/3 of the rest (balance). So, the widow had 1/3 and each son 1/3 divided by 3 or 2/9.
1/3 + 2/9 = roughly 0.55%.
120,000 = 0.55% of X
C is the answer
Now, the widow had 1/3, and 3 sons 1/3 of the rest (balance). So, the widow had 1/3 and each son 1/3 divided by 3 or 2/9.
1/3 + 2/9 = roughly 0.55%.
120,000 = 0.55% of X
C is the answer
The answers are indeed precise.
Here is the way I did it.
W = 1/3 H
1 son = 1/3 (2/3 H) = 2/9H
Now 1/3H + 2/9 H = 120000
H = 216000
