GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
On a certain train, children’s tickets cost $6 and adult tic
[#permalink]
Updated on: 20 Jul 2018, 08:36
Updated on: 20 Jul 2018, 08:36
1
Expert Reply
3
Bookmarks
00:00
Question Stats:
66% (01:32) correct
33% (01:46) wrong based on 151 sessions
Hide Show timer Statistics
On a certain train, tickets cost $6 each for children and $9 each for adults. The total train ticket cost for a certain group of six passengers was between $44 and $50.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of children in the group |
The number of adults in the group |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: On a certain train, children’s tickets cost $6 and adult tic
[#permalink]
28 May 2018, 13:47
28 May 2018, 13:47
2
1
Expert Reply
Explanation
Even though the range of costs ($44 to $50) is fairly small, there is still more than one possibility. A good way to work this out is to start with the simplest scenario: 3 adults and 3 children. Their tickets would cost 3(9) + 3(6) = $45. That’s in the range, so it’s one possibility.
Since children’s tickets are cheaper, you don’t want to add more children to the mix (4 children, 2 adults will give you too small a total), but try switching out 1 child for 1 adult.
For 4 adults and 2 children, tickets would cost 4(9) + 2(6) = $48. Thus, Quantity A and Quantity B could be equal, or Quantity B could be greater, so the relationship cannot be determined from the information given.
Hence option D is correct!
Even though the range of costs ($44 to $50) is fairly small, there is still more than one possibility. A good way to work this out is to start with the simplest scenario: 3 adults and 3 children. Their tickets would cost 3(9) + 3(6) = $45. That’s in the range, so it’s one possibility.
Since children’s tickets are cheaper, you don’t want to add more children to the mix (4 children, 2 adults will give you too small a total), but try switching out 1 child for 1 adult.
For 4 adults and 2 children, tickets would cost 4(9) + 2(6) = $48. Thus, Quantity A and Quantity B could be equal, or Quantity B could be greater, so the relationship cannot be determined from the information given.
Hence option D is correct!
Re: On a certain train, children’s tickets cost $6 and adult tic
[#permalink]
10 Oct 2018, 03:53
10 Oct 2018, 03:53
3
1
Bookmarks
Let the number of children = c and the number of adults = a
6*c + 9*a = (44 to 50)
c + a = 6
c = 6 - a
6*(6 - a) + 9*a = (44 to 50)
3*a = (8 to 14) then a can be 3 or 4 so there are two cases [one where a = 3 equal c = 3, while the other (a = 4) > (c = 2)]
So the correct answer is D)The relationship cannot be determined from the information given.
6*c + 9*a = (44 to 50)
c + a = 6
c = 6 - a
6*(6 - a) + 9*a = (44 to 50)
3*a = (8 to 14) then a can be 3 or 4 so there are two cases [one where a = 3 equal c = 3, while the other (a = 4) > (c = 2)]
So the correct answer is D)The relationship cannot be determined from the information given.
