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Re: With 4 identical servers working at a constant rate, a new I [#permalink]
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4 identical servers work at a constant rate can process 9,600 search requests per hour.

1 server work at a constant rate can process 2400 search request per hour.

so, 6 server work at a constant rate can process 2400*6 = 14400 search request per hour.

so it will take 216,000/14,400 = 15 hours to process 216,000 search requests.

Answer: A
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Re: With 4 identical servers working at a constant rate, a new I [#permalink]
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Explanation

If the search provider adds 2 identical servers to the original 4, there are now 6 servers.

Because 6 ÷ 4 = 1.5, the rate at which all 6 servers work is 1.5 times the rate at which 4 servers work:

9,600 searches per hour × 1.5 = 14,400 searches per hour

Now apply this rate to the given amount of work (216,000 searches), using the W = RT formula:

216,000 = 14,400 × T
216,000 ÷ 14,400 = 15 hours
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Re: With 4 identical servers working at a constant rate, a new I [#permalink]
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As 4 servers can process 9600 requests in 1 hour,
• 1 server can process 96004=240096004=2400 requests per hour

If 2 more, servers are added,
• Total number of servers = 4 + 2 = 6
• Total requests processed in 1 hour = 2400 * 6 = 14400

Therefore, to process 216000 search requests,
• The servers will take 21600014400=1521600014400=15 hours

Hence, the correct answer is option A.
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Re: With 4 identical servers working at a constant rate, a new I [#permalink]
1
4 identical servers processes 9600 search requests per hr
1 identical server process 9600/4 or 2400 search requests per hr
rate=2400
adding 2 servers ,total servers =4+2=6
work=rate*time*number
216000=2400*time*6
time=216000/(2400*6)=15 hs
ans A
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Re: With 4 identical servers working at a constant rate, a new I [#permalink]
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