Carcass wrote:
In a certain game, a player flips a coin to determine movement. Every toss of the coin lands with either a head facing up or a tail facing up. If a head is facing up, the player moves forward 10 squares, and if a tail is facing up, he moves backward 13 squares. After flipping the coin 120 times, the player is four squares forward of his starting position. How many of the 120 flips showed a head facing up?
\(H + T = 120\) ........ (1)
\(10H - 13T = 4\) ........ (2)
Multiplying (1) by \(10\) and subtracting (2) from it:
\(10H + 10T = 1200\) ........ (1)
\(10H - 13T = 4\) ........ (2)
\(23T = 1196\)
\(T = 52\)
So, \(H = 120 - 52 = 68\)