Last visit was: 21 Nov 2024, 16:43 It is currently 21 Nov 2024, 16:43

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
avatar
Intern
Intern
Joined: 05 Jan 2016
Posts: 28
Own Kudos [?]: 50 [0]
Given Kudos: 0
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 30003
Own Kudos [?]: 36341 [0]
Given Kudos: 25927
Send PM
avatar
Intern
Intern
Joined: 05 Jan 2016
Posts: 28
Own Kudos [?]: 50 [0]
Given Kudos: 0
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 30003
Own Kudos [?]: 36341 [0]
Given Kudos: 25927
Send PM
Re: Gre PREP Question [#permalink]
Expert Reply
GREhelp wrote:
Sorry for the inconvenience, the source of the question is Manhattan Prep GRE Algebra Practice book and the answer was 6. It was a fill in the blank question.

I understand how you solved it, the explanation makes perfect sense. Where I struggled was that after substituting the 4 into the problem, and getting -11. I did not know what to do next. How did you know that you need to set the equation to -11?

The first thing I tried to do when I first saw this problem was to try to factor it out but how do you factor a number that is adding +13. The only two numbers that multiply to equal 13 is (1 and 13) however they do not sum to 10.

THANKS SO MUCH!!


Please Grehelp: formatting properly the question: title, questions, and answer choices.

As for the question, you do need to find your unknown that is K. As such, substituting x=4 in your equation it becomes \(4^2\)-10*4+13=K >>> K=-11

Then you do have \(x^2\)-10X+13=-11 >>>>>> \(x^2\) -10X+13+11=0 >>>> \(x^2\)-10X+24=0

The best and faster way to solve for

Hope this helps
Prep Club for GRE Bot
Re: Gre PREP Question [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne