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If the sum of three consecutive integers is doubled, the result is 71
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25 Aug 2021, 10:35
25 Aug 2021, 10:35
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If the sum of three consecutive integers is doubled, the result is 71 more than \(\frac{5}{2}\) times the greatest of the three integers. What is the value of the greatest integer?
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22
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Re: If the sum of three consecutive integers is doubled, the result is 71
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25 Aug 2021, 10:49
25 Aug 2021, 10:49
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Carcass wrote:
If the sum of three consecutive integers is doubled, the result is 71 more than \(\frac{5}{2}\) times the greatest of the three integers. What is the value of the greatest integer?
Show: :: OA
22
Let the integers be (x - 1), x, and (x + 1)
\(2[(x - 1) + x + (x + 1)] = \frac{5}{2}(x + 1) + 71\)
\(2(3x) = \frac{5}{2}(x + 1) + 71\)
\(6x = \frac{5x}{2} + \frac{5}{2} + 71\)
\(\frac{7x}{2} = \frac{147}{2}\)
\(7x = 147\)
\(x = 21\)
Greatest integer = 22
gmatclubot
Re: If the sum of three consecutive integers is doubled, the result is 71 [#permalink]
25 Aug 2021, 10:49
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