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75% of all the boys and 48% of all the girls at Smith High S
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14 Jul 2018, 05:07
14 Jul 2018, 05:07
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Question Stats:
81% (01:38) correct
18% (02:10) wrong based on 32 sessions
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75% of all the boys and 48% of all the girls at Smith High School take civics. If there are 20% fewer boys than there are girls in the school, what percent of all the students take civics?
Show: :: OA
60%
Re: 75% of all the boys and 48% of all the girls at Smith High S
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14 Jul 2018, 05:26
14 Jul 2018, 05:26
Expert Reply
Explanation
Use smart numbers. There are 20% fewer boys than girls, so choose 100 for the number of girls (100 is a good number to pick for percent problems). Thus, there are (100)(0.8) = 80 boys in the school.
If 75% of all the boys take civics, then 0.75(80) = 60 boys take civics. If 48% of all the girls take civics, then 0.48(100) = 48 girls take civics.
Therefore, 60 + 48 = 108 students take civics and there are 180 total students:
\(\frac{108}{180} \times 100\%=60\%\)
Use smart numbers. There are 20% fewer boys than girls, so choose 100 for the number of girls (100 is a good number to pick for percent problems). Thus, there are (100)(0.8) = 80 boys in the school.
If 75% of all the boys take civics, then 0.75(80) = 60 boys take civics. If 48% of all the girls take civics, then 0.48(100) = 48 girls take civics.
Therefore, 60 + 48 = 108 students take civics and there are 180 total students:
\(\frac{108}{180} \times 100\%=60\%\)
Re: 75% of all the boys and 48% of all the girls at Smith High S
[#permalink]
21 Jun 2023, 06:42
21 Jun 2023, 06:42
Let’s solve this problem together. Let’s assume that there are 100 girls in the school. Since there are 20% fewer boys than girls, there are 80 boys in the school. If 75% of the boys take civics, that means 60 boys take civics. If 48% of the girls take civics, that means 48 girls take civics. So, out of a total of 180 students (100 girls + 80 boys), 108 students (60 boys + 48 girls) take civics. Therefore, 60% of all the students at Smith High School take civics.
