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If the mean of 6 consecutive integers is 8.5, what is the pr
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02 Jan 2021, 02:41
02 Jan 2021, 02:41
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If the mean of 6 consecutive integers is 8.5, what is the product of the first and the last?
Kudos for the right answer and explanation
Show: :: OA
66
Kudos for the right answer and explanation
Re: If the mean of 6 consecutive integers is 8.5, what is the pr
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02 Jan 2021, 08:29
02 Jan 2021, 08:29
six consecutive integers.
Mean = Sum of all / 6
Sum of all = 8.5 * 6 = 51
Let's take six consecutive integers as
a-3 a-2 a-1 a a+1 a+2
Sum = 6a-3 = 51
6a = 54
a = 9
So nos are
6 7 8 9 10 11
Multiplication of first and last = 11 * 6 = 66
Answer 66
Mean = Sum of all / 6
Sum of all = 8.5 * 6 = 51
Let's take six consecutive integers as
a-3 a-2 a-1 a a+1 a+2
Sum = 6a-3 = 51
6a = 54
a = 9
So nos are
6 7 8 9 10 11
Multiplication of first and last = 11 * 6 = 66
Answer 66
Re: If the mean of 6 consecutive integers is 8.5, what is the pr
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13 Jun 2022, 00:54
13 Jun 2022, 00:54
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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