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Frank the Fencemaker needs to fence in a rectangular yard. He fences i
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03 Feb 2023, 08:39
03 Feb 2023, 08:39
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50% (01:34) correct
50% (01:15) wrong based on 4 sessions
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Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one 40-foot side of the yard. The yard has an area of 280 square feet. How many feet of fence does Frank use?
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54 feet
Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences i
[#permalink]
20 Feb 2023, 08:10
20 Feb 2023, 08:10
Expert Reply
OE
You know that one side of the yard is 40 feet long, so call this the length.
You also know that the area of the yard is 280 square feet. In order to determine the perimeter, you must know the width of the yard:
A = l x w
280 = 40W=7
Frank fences the two 7-foot sides and one of the 40-foot sides. Therefore, he needs 40 + 2(7) = 54 feet of fence.
You know that one side of the yard is 40 feet long, so call this the length.
You also know that the area of the yard is 280 square feet. In order to determine the perimeter, you must know the width of the yard:
A = l x w
280 = 40W=7
Frank fences the two 7-foot sides and one of the 40-foot sides. Therefore, he needs 40 + 2(7) = 54 feet of fence.
gmatclubot
Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences i [#permalink]
20 Feb 2023, 08:10
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