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If the average of a and b is
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30 Jul 2023, 23:34
30 Jul 2023, 23:34
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20% (02:36) wrong based on 10 sessions
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If the average of a and b is \(\frac{m}{2}\) , average of b and c is m, and the average of a and c is \(\frac{3m}{2}\) then the average of a, b, c is how many times of m?
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If the average of a and b is
[#permalink]
17 Sep 2023, 02:02
17 Sep 2023, 02:02
Expert Reply
OE
We are given that the average of ๐ and ๐ is ๐/2 , average of ๐ and ๐ is ๐ and the average of ๐ and ๐ is 3๐/2
We need to find that the average of ๐, ๐ and ๐ is how many times of ๐.
Since, the average of ๐ and ๐ is ๐/2
๐+๐/2= ๐/2
๐ + ๐ =๐/2ร 2
๐ + ๐ = ๐ (eqn.1)
Average of ๐ and ๐ is ๐
So similarly, ๐ + ๐ = 2๐ (eqn.2)
Average of ๐ and ๐ is 3๐/2
So, ๐ + ๐ =3๐/2ร 2
๐ + ๐ = 3๐ (eqn.3)
Adding (eqn.1), (eqn.2) and (eqn.3) we get,
(๐ + ๐) + (๐ + ๐) + (๐ + ๐) = ๐ + 2๐ + 3๐
2๐ + 2๐ + 2๐ = 6๐
๐ + ๐ + ๐ = 3๐
Average of ๐, ๐ and ๐ =a+b+c/3=3m/3=m or 1
We are given that the average of ๐ and ๐ is ๐/2 , average of ๐ and ๐ is ๐ and the average of ๐ and ๐ is 3๐/2
We need to find that the average of ๐, ๐ and ๐ is how many times of ๐.
Since, the average of ๐ and ๐ is ๐/2
๐+๐/2= ๐/2
๐ + ๐ =๐/2ร 2
๐ + ๐ = ๐ (eqn.1)
Average of ๐ and ๐ is ๐
So similarly, ๐ + ๐ = 2๐ (eqn.2)
Average of ๐ and ๐ is 3๐/2
So, ๐ + ๐ =3๐/2ร 2
๐ + ๐ = 3๐ (eqn.3)
Adding (eqn.1), (eqn.2) and (eqn.3) we get,
(๐ + ๐) + (๐ + ๐) + (๐ + ๐) = ๐ + 2๐ + 3๐
2๐ + 2๐ + 2๐ = 6๐
๐ + ๐ + ๐ = 3๐
Average of ๐, ๐ and ๐ =a+b+c/3=3m/3=m or 1
gmatclubot
If the average of a and b is [#permalink]
17 Sep 2023, 02:02
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