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BC is a diameter of circle O and is parallel to
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06 Aug 2020, 05:24
06 Aug 2020, 05:24
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61% (03:09) correct
38% (03:48) wrong based on 36 sessions
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\(\overline{BC}\) is a diameter of circle O and is parallel to \(\overline{YZ}\) If the length of arc ABC is 22π and the length of minor arc CD is 11π, then what is the positive difference between the degree measures of \(∠ OYZ\) and \(∠ YOZ\)?
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80
Re: BC is a diameter of circle O and is parallel to
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07 Aug 2020, 04:28
07 Aug 2020, 04:28
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ZOB = 40 . AOC (the larger angle) = 220.
To find the radius:
pi * r^2 * 220/360 = 22*pi
r = 6.
To find angle DOC ($):
pi * 6^2 * $/360 = 11 * pi
DOC=$=110.
YOZ = 360 - 220 -110 = 30.
OYZ = 180 - 30 - 40 = 110.
So the difference OYZ - YOZ = 80.
To find the radius:
pi * r^2 * 220/360 = 22*pi
r = 6.
To find angle DOC ($):
pi * 6^2 * $/360 = 11 * pi
DOC=$=110.
YOZ = 360 - 220 -110 = 30.
OYZ = 180 - 30 - 40 = 110.
So the difference OYZ - YOZ = 80.
Re: BC is a diameter of circle O and is parallel to
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09 Aug 2020, 11:35
09 Aug 2020, 11:35
1
Aaka wrote:
ZOB = 40 . AOC (the larger angle) = 220.
To find the radius:
pi * r^2 * 220/360 = 22*pi
r = 6.
To find angle DOC ($):
pi * 6^2 * $/360 = 11 * pi
DOC=$=110.
YOZ = 360 - 220 -110 = 30.
OYZ = 180 - 30 - 40 = 110.
So the difference OYZ - YOZ = 80.
To find the radius:
pi * r^2 * 220/360 = 22*pi
r = 6.
To find angle DOC ($):
pi * 6^2 * $/360 = 11 * pi
DOC=$=110.
YOZ = 360 - 220 -110 = 30.
OYZ = 180 - 30 - 40 = 110.
So the difference OYZ - YOZ = 80.
r is not 6.
r=18
