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A 20-foot ladder leaning against a vertical wall with the ba
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22 Aug 2018, 09:14
22 Aug 2018, 09:14
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Question Stats:
73% (02:01) correct
26% (02:05) wrong based on 191 sessions
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A 20-foot ladder leaning against a vertical wall with the base of the ladder 10 feet from the wall is pulled 2 feet farther out from the wall, causing the top of the ladder to drop x feet.
Quantity A |
Quantity B |
x |
2 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
Re: A 20-foot ladder leaning against a vertical wall with the ba
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25 Aug 2018, 11:00
25 Aug 2018, 11:00
5
Carcass wrote:
Attachment:
triangle.jpg
A 20-foot ladder leaning against a vertical wall with the base of the ladder 10 feet from the wall is pulled 2 feet farther out from the wall, causing the top of the ladder to drop x feet.
Quantity A |
Quantity B |
x |
2 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for R.A.E
\(20^2 = 12^2 + A^2\) -> \(A^2 = 400 - 144 = 256\) -> \(A = \sqrt{256} = 16\)
Similarly,\(20^2 = 10^2 + (16 + x)^2\) -> \((16 + x)^2 = 300\)
As 18^2 = 324 > 300 and x must be less than 2
Therefore, we can conclude that Quantity B is greater (Option B)
General Discussion
Re: A 20-foot ladder leaning against a vertical wall with the ba
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28 Aug 2018, 21:34
28 Aug 2018, 21:34
3
1
Use Pythagorean theorum for two lenghts of base(first 10 and then 12) keeping the ladder lengh as 20 to find the difference of the height . the defferece is X .
in first case height will come as 17.32
in second case height will come as 16.00
so X wil be 1.32 < than 2.
in first case height will come as 17.32
in second case height will come as 16.00
so X wil be 1.32 < than 2.
