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If K > 0
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Updated on: 24 Jul 2021, 23:57
Updated on: 24 Jul 2021, 23:57
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Question Stats:
96% (01:04) correct
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If K > 0
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{{5k^2-1}}{{2k^3}}\) |
\(\frac{5}{2k}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If K > 0
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30 Nov 2018, 13:18
30 Nov 2018, 13:18
pranab01 wrote:
If K > 0
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{{5k^2-1}}{{2k^3}}\) |
\(\frac{5}{2k}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Since k is positive, we know that 2k³ is POSITIVE
This means we can safely multiply both quantities by 2k³ to get:
Quantity A: 5k² - 1
Quantity B: 10k³/2k
Simplify Quantity B to get:
Quantity A: 5k² - 1
Quantity B: 5k²
Subtract 5k² from both quantities to get:
Quantity A: -1
Quantity B: 0
Quantity B is greater.
Answer: B
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gmatclubot
Re: If K > 0 [#permalink]
30 Nov 2018, 13:18
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