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If K > 0

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pranab223
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If K > 0 [#permalink] New post   Updated on: 24 Jul 2021, 23:57
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Question Stats:

96% (01:05) correct 3% (01:57) wrong based on 29 sessions

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If K > 0

Quantity A
Quantity B
\(\frac{{5k^2-1}}{{2k^3}}\)
\(\frac{5}{2k}\)




A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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B

Originally posted by pranab223 on 30 Nov 2018, 10:31.
Last edited by Ks1859 on 24 Jul 2021, 23:57, edited 2 times in total.
Edited by ks1859
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Re: If K > 0 [#permalink] New post   30 Nov 2018, 13:18
pranab01 wrote:
If K > 0

Quantity A
Quantity B
\(\frac{{5k^2-1}}{{2k^3}}\)
\(\frac{5}{2k}\)




A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Since k is positive, we know that 2k³ is POSITIVE
This means we can safely multiply both quantities by 2k³ to get:
Quantity A: 5k² - 1
Quantity B: 10k³/2k

Simplify Quantity B to get:
Quantity A: 5k² - 1
Quantity B: 5k²

Subtract 5k² from both quantities to get:
Quantity A: -1
Quantity B: 0

Quantity B is greater.

Answer: B

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Re: If K > 0 [#permalink]
30 Nov 2018, 13:18
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