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The average ages of the players on team A and team B, are 2
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11 Apr 2019, 16:16
11 Apr 2019, 16:16
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75% (00:48) correct
24% (00:53) wrong based on 61 sessions
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The average ages of the players on team A and team B, are 20 and 30 years, respectively. The average age of the players of the teams together is 26.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of players on team A |
The number of players on team B |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: The average ages of the players on team A and team B, are 2
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11 Apr 2019, 20:23
11 Apr 2019, 20:23
2
Carcass wrote:
The average ages of the players on team A and team B, are 20 and 30 years, respectively. The average age of the players of the teams together is 26.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of players on team A |
The number of players on team B |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Answer is B.
Team A = 20x
Team B = 30y
So combined average is
--> (20x + 30y)/(x+y) = 26;
--> 26x + 26y = 20x + 30y;
Hence 6x=4y
Therefore x/y = 2/3
Re: The average ages of the players on team A and team B, are 2
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12 Apr 2019, 14:34
12 Apr 2019, 14:34
3
When you are averaging the total number of items in two groups, combined, the final average will be closest to the average for the larger of the two groups.
In this case, 26 is closer to 30 (team B) than to 20 (team A)
In this case, 26 is closer to 30 (team B) than to 20 (team A)
