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Sets S and T satisfy the conditions that all the numbers in
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27 May 2020, 21:33
27 May 2020, 21:33
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70% (00:32) correct
29% (00:46) wrong based on 24 sessions
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Sets S and T satisfy the conditions that all the numbers in set S are in set T and the average of numbers in set S is equal to the average of numbers in set T
A. Quantity A is greater
B. Quantity B is greater
C. Both are equal
D. Cannot be determined
Quantity A |
Quantity B |
Standard Deviation of set S |
Standard Deviation of set T |
A. Quantity A is greater
B. Quantity B is greater
C. Both are equal
D. Cannot be determined
Re: Sets S and T satisfy the conditions that all the numbers in
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28 May 2020, 08:25
28 May 2020, 08:25
Expert Reply
T include S and they could have the exact numbers or T could have more
A=S/N of S and T could be the same BUT S has only numbers which could be 1 and the SD is just 1
And T could have the exact numbers, the average but the SD could be 5
Or vice-versa
The answer is D
A=S/N of S and T could be the same BUT S has only numbers which could be 1 and the SD is just 1
And T could have the exact numbers, the average but the SD could be 5
Or vice-versa
The answer is D
Re: Sets S and T satisfy the conditions that all the numbers in
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22 Sep 2025, 22:51
22 Sep 2025, 22:51
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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