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x=4/3 r^2h^2
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20 Oct 2018, 04:33
20 Oct 2018, 04:33
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Question Stats:
92% (00:45) correct
7% (00:55) wrong based on 105 sessions
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\(x=\frac{4}{3} r^2h^2\)
\(x=1\)
\(r\) and \(h\) are positive.
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
\(x=1\)
\(r\) and \(h\) are positive.
Quantity A |
Quantity B |
\(h\) |
\(\frac{\sqrt{3}}{2r}\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Re: x=4/3 r^2h^2
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21 Oct 2018, 06:07
21 Oct 2018, 06:07
1
From eqn,
\(1= \frac{4r^2}{3} * h^2\)
or, \(\frac{3}{4} = r^2*h^2\)
or \(\frac{3}{4r^2} = h^2\)
or,\(\sqrt{\frac{3}{4r^2}}=h\)
or, \(\sqrt{3}/2r\) = h
\(1= \frac{4r^2}{3} * h^2\)
or, \(\frac{3}{4} = r^2*h^2\)
or \(\frac{3}{4r^2} = h^2\)
or,\(\sqrt{\frac{3}{4r^2}}=h\)
or, \(\sqrt{3}/2r\) = h
Re: x=4/3 r^2h^2
[#permalink]
21 Oct 2018, 06:08
21 Oct 2018, 06:08
1
Carcass wrote:
\(x=\frac{4}{3} r^2h^2\)
\(x=1\)
\(r\) and \(h\) are positive.
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
\(x=1\)
\(r\) and \(h\) are positive.
Quantity A |
Quantity B |
\(h\) |
\(\frac{\sqrt{3}}{2r}\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
\(x=\frac{4}{3} r^2h^2\)
or \(1 = \frac{4}{3} r^2h^2\)
or \(h^2 = \frac{3}{4r^2}\)
or \(h = \frac{\sqrt{3}}{2r}\)
since h is positive, so only positive solution is considered
Therefore option C
