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In the country of XYZ, the I-score of a politician is computed
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10 Aug 2021, 05:42
10 Aug 2021, 05:42
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69% (03:31) correct
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In the country of XYZ, the I-score of a politician is computed from the following formula:
\(I = \frac{41ab^2c^3}{d^2}\), in which the variables \(a, b, c,\) and \(d\) represent various perceived attributes of the politician, all of which are measured with positive numbers.
Mayor Flower’s I-score is 150% higher than that of Councilor Plant; moreover, the values of \(a, b,\) and \(c\) are 60% higher, 40% higher, and 20% lower, respectively, for Mayor Flower than for Councilor Plant. The value of \(d\) for Councilor Plant is \(x\)% higher or lower than the corresponding value for Mayor Flower.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
\(I = \frac{41ab^2c^3}{d^2}\), in which the variables \(a, b, c,\) and \(d\) represent various perceived attributes of the politician, all of which are measured with positive numbers.
Mayor Flower’s I-score is 150% higher than that of Councilor Plant; moreover, the values of \(a, b,\) and \(c\) are 60% higher, 40% higher, and 20% lower, respectively, for Mayor Flower than for Councilor Plant. The value of \(d\) for Councilor Plant is \(x\)% higher or lower than the corresponding value for Mayor Flower.
Quantity A |
Quantity B |
\(x\) |
14.50% |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
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GRE 1: Q160 V152
In the country of XYZ, the I-score of a politician is computed
[#permalink]
Updated on: 14 Aug 2021, 09:08
Updated on: 14 Aug 2021, 09:08
1
revised..
let's check change in \(ab^2c^3\)
\((1+3/5)*(1+2/5)^2*(1-1/5)^3=8/5 * 49/5^2 * 64/5^3 = (8*49*64)/5^6 = 1.6\)
Since I is inversely related with \(d^2\), every increase in I will result in decrease of \(d^2\), unless changes of \(a, b, c\) are outweighing the change in I. Change in I is 150% higher for Flower. Change in I is 2.5 vs changes of \(a, b, c\) equal to 1.6. Change requested is lower or higher, hence sq.root(2.5/1.6)=sq.root(25/10 * 10/16)=5/4=1.25 or 25%
Answer must be A
let's check change in \(ab^2c^3\)
\((1+3/5)*(1+2/5)^2*(1-1/5)^3=8/5 * 49/5^2 * 64/5^3 = (8*49*64)/5^6 = 1.6\)
Since I is inversely related with \(d^2\), every increase in I will result in decrease of \(d^2\), unless changes of \(a, b, c\) are outweighing the change in I. Change in I is 150% higher for Flower. Change in I is 2.5 vs changes of \(a, b, c\) equal to 1.6. Change requested is lower or higher, hence sq.root(2.5/1.6)=sq.root(25/10 * 10/16)=5/4=1.25 or 25%
Answer must be A
Originally posted by motion2020 on 10 Aug 2021, 17:16.
Last edited by motion2020 on 14 Aug 2021, 09:08, edited 1 time in total.
Last edited by motion2020 on 14 Aug 2021, 09:08, edited 1 time in total.
Re: In the country of XYZ, the I-score of a politician is computed
[#permalink]
14 Aug 2021, 05:58
14 Aug 2021, 05:58
1
[quote="motion2020"]revised..
let's check change in \(ab^2c^3\)
\((1+3/5)*(1+2/5)^2*(1-1/5)^3=8/5 * 49/5^2 * 64/5^3 = (8*49*64)/5^6 = 1.6\)
Since I is inversely related with \(d^2\), every increase in I will result in decrease of \(d^2\), unless changes of \(a, b, c\) are outweighing the change in I. Change in I is 150% higher for Flower. Change in I is 2.5 vs changes of \(a, b, c\) equal to 1.6. Change requested is lower or higher, hence sq.root(2.5/1.6)=sq.root(25/10 * 10/16)=sq.root(5/4)=1.25 or 25%
Answer must be A[/It also says that x% is higher or lower what do we conclude from that do we take higher or lower ]
let's check change in \(ab^2c^3\)
\((1+3/5)*(1+2/5)^2*(1-1/5)^3=8/5 * 49/5^2 * 64/5^3 = (8*49*64)/5^6 = 1.6\)
Since I is inversely related with \(d^2\), every increase in I will result in decrease of \(d^2\), unless changes of \(a, b, c\) are outweighing the change in I. Change in I is 150% higher for Flower. Change in I is 2.5 vs changes of \(a, b, c\) equal to 1.6. Change requested is lower or higher, hence sq.root(2.5/1.6)=sq.root(25/10 * 10/16)=sq.root(5/4)=1.25 or 25%
Answer must be A[/It also says that x% is higher or lower what do we conclude from that do we take higher or lower ]
