GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 17Live Online Classes with Top GRE Expert Rich Zwelling
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Tues/Thur Sept 7, 2026---Feb. 2, 2027, 1:00pm-3:00pm EST
Dec 14Live Online Classes with Top GRE Expert Michael Butville
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Mon/Wed Dec. 14, 2026---Feb. 22, 2027, 8:00pm-10:00pm EST
Fraction of numbers from 0 through 1000 that are divisible b
[#permalink]
03 May 2019, 02:02
03 May 2019, 02:02
Expert Reply
1
Bookmarks
00:00
Question Stats:
80% (01:02) correct
19% (01:36) wrong based on 73 sessions
Hide Show timer Statistics
Quantity A |
Quantity B |
Fraction of numbers from 0 through 1000 that are divisible by both 7 and 10 |
Fraction of numbers from 0 through 1000 that are divisible by both 5 and 14 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: Fraction of numbers from 0 through 1000 that are divisible b
[#permalink]
05 May 2019, 11:19
05 May 2019, 11:19
5
In order to be divisible by both 7 and 10, a number has to be divisible by 7, 2, and 5.
In order to be divisible by both 5 and 14, a number has to be divisible by 5, 2, and 7.
Answer: C.
Hope this helps.
In order to be divisible by both 5 and 14, a number has to be divisible by 5, 2, and 7.
Answer: C.
Hope this helps.
General Discussion
Re: Fraction of numbers from 0 through 1000 that are divisible b
[#permalink]
03 May 2019, 05:22
03 May 2019, 05:22
1
For qty A the count of numbers that are divisible by both 7 and 10 are those numbers between 0 and 1000 that are divisible by the LCM of 7 and 10. Since 7 is a prime number the LCM of 7 and 10 is 70. We get the count of numbers as \(\frac{980}{70}\) = 14. We take 980 because it is the last number less than or equal to 1000 which is divisible by 70. The question does not say that either 0 or 1000 or both are inclusive so in such situation take 1 of the number as inclusive and another exclusive.
For qty B use the same procedure we get the LCM of 5 and 14 as 70 because 5 is a prime number so we simply multiply the two quantities in question. As the LCM for both qty A and B is same and the limit for both the quantity is between 0 and 1000 hence for qty B as well the count of numbers is the same i.e. 14.
Therefore option C
If we had taken 0 and 1000 both inclusive the calculation would be slightly different i.e. \(\frac{980-0}{70}\) + 1
For qty B use the same procedure we get the LCM of 5 and 14 as 70 because 5 is a prime number so we simply multiply the two quantities in question. As the LCM for both qty A and B is same and the limit for both the quantity is between 0 and 1000 hence for qty B as well the count of numbers is the same i.e. 14.
Therefore option C
If we had taken 0 and 1000 both inclusive the calculation would be slightly different i.e. \(\frac{980-0}{70}\) + 1
