GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
GRE question
[#permalink]
Updated on: 19 Jun 2019, 03:42
Updated on: 19 Jun 2019, 03:42
00:00
Question Stats:
40% (00:57) correct
59% (00:59) wrong based on 22 sessions
Hide Show timer Statistics
\(a^2-2ab+b^2=0\)
\(b=\frac{16}{a}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(b=\frac{16}{a}\)
Quantity A |
Quantity B |
a |
4 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Originally posted by rahulroy1676 on 19 Jun 2019, 01:05.
Last edited by Carcass on 19 Jun 2019, 03:42, edited 2 times in total.
Last edited by Carcass on 19 Jun 2019, 03:42, edited 2 times in total.
Edited by Carcass
Re: GRE question
[#permalink]
19 Jun 2019, 01:06
19 Jun 2019, 01:06
By factorizing the quadratic equation, you get (a−b)(a−b)=0.
From this, we can say that a−b=0 which means a=b.
Thus, b=16a can be written as b=16b which implies b2=16, and b = 4 or -4.
If b = 4, then both the quantities are equal and if b = -4, then Quantity B is greater.
Therefore, the correct answer is D.
From this, we can say that a−b=0 which means a=b.
Thus, b=16a can be written as b=16b which implies b2=16, and b = 4 or -4.
If b = 4, then both the quantities are equal and if b = -4, then Quantity B is greater.
Therefore, the correct answer is D.
gmatclubot
Re: GRE question [#permalink]
19 Jun 2019, 01:06
Moderators:
