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Given that |15-|x-3||<5 and x<0
[#permalink]
22 Sep 2026, 22:58
22 Sep 2026, 22:58
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Question Stats:
55% (02:09) correct
44% (02:12) wrong based on 9 sessions
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Given that \(|15-|x-3||<5\) and \(x<0
\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
\)
Quantity A |
Quantity B |
\(x\) |
\(-5\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
- Part of the project: GRE Daily Quant Challenge ALL 4 CORE QUANT AREAS
- Also replying to the unanswered questions
Re: Given that |15-|x-3||<5 and x<0
[#permalink]
23 Sep 2026, 23:50
23 Sep 2026, 23:50
1
Case - 1
15 - x + 3 < 5
x > 13 NOT POSSIBLE
Case - 2
15 + x - 3 < 5
x < -7
Case - 3
-15 + x - 3 < 5
x < 23 Already know as x < 0
Case - 4
-15 - x + 3 < 5
x > -17
From Case 2, 4 and the given condition x <0
-17 < x < -7
15 - x + 3 < 5
x > 13 NOT POSSIBLE
Case - 2
15 + x - 3 < 5
x < -7
Case - 3
-15 + x - 3 < 5
x < 23 Already know as x < 0
Case - 4
-15 - x + 3 < 5
x > -17
From Case 2, 4 and the given condition x <0
-17 < x < -7
gmatclubot
Re: Given that |15-|x-3||<5 and x<0 [#permalink]
23 Sep 2026, 23:50
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