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Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
3x + 5y = -20 and 5x + 11y = -39
[#permalink]
15 Oct 2019, 06:58
15 Oct 2019, 06:58
1
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Question Stats:
81% (01:46) correct
18% (01:51) wrong based on 48 sessions
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\(3x+5y=-20\)
\(5x+11y=-39\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(5x+11y=-39\)
Quantity A |
Quantity B |
\(x\) |
\(y\) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: 3x + 5y = -20 and 5x + 11y = -39
[#permalink]
15 Oct 2019, 07:29
15 Oct 2019, 07:29
2
GreenlightTestPrep wrote:
\(3x+5y=-20\)
\(5x+11y=-39\)
\(5x+11y=-39\)
Quantity A |
Quantity B |
\(x\) |
\(y\) |
One approach is to solve the system for x and y (which can take a while).
Another approach is that we can create an equation with ONE x and ONE y.
Take:
\(3x+5y=-20\)
\(5x+11y=-39\)
Multiply both sides of the TOP equation by 2 to get:
\(6x+10y=-40\)
\(5x+11y=-39\)
Subtract the bottom equation from the top equation to get: \(x-y=-1\)
GIVEN:
Quantity A: \(x\)
Quantity B: \(y\)
Subtract y from both quantities to get:
Quantity A: \(x-y\)
Quantity B: \(0\)
Since we now know that \(x-y=-1\), we can rewrite Quantity A as follows:
Quantity A: \(-1\)
Quantity B: \(0\)
Answer: B
Cheers,
Brent
gmatclubot
Re: 3x + 5y = -20 and 5x + 11y = -39 [#permalink]
15 Oct 2019, 07:29
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